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sleet_krkn [62]
3 years ago
13

I need to know the answer to this?

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

5 min person wit 10 min person

5 min person wit 20 min person and 5 min person back

5 min person wit 25 min person and 5 min person back

5 min person need to slow down ea. time

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A steep hill has a greater slope than a flat plain. What does the slope of the line on a graph describe?
oee [108]
The slope of a line on a graph describes how "steep" the curve is by using the rise divided by the run (y=mx+b).  The slope on the line graph usually represents how much of an increase or decrease is occurring per each unit
7 0
3 years ago
The sum of Jack and Jill's ages is 84. If Jill is twenty times
9966 [12]

Answer:

4.2

Step-by-step explanation:

84 divided by 20  4.2

7 0
3 years ago
-7/4=2/5t what1 it the value of t
harkovskaia [24]

Check the attached answer.

8 0
3 years ago
A family of 8 went out to dinner. Each person either ordered the lobster dinner, which costs $25, or the steak dinner which cost
defon

Answer: 6 people ordered for the lobster dinner.

2 people ordered for the steak dinner.

Step-by-step explanation:

Let x represent the number of people that ordered the lobster dinner.

Let y represent the number of people that ordered the steak dinner.

A family of 8 went out to dinner. This means that

x + y = 8

Each person either ordered the lobster dinner, which costs $25, or the steak dinner which cost $20. The total cost of all the meals is $190. This means that

25x + 20y = 190 - - - - - - - - - -- -1

Substituting x = 8 - y into equation 1, it becomes

25(8 - y) + 20y = 190

200 - 25y + 20y = 190

- 25y + 20y = 190 - 200

- 5y = - 10

y = - 10/ - 5

y = 2

x = 8 - y = 8 - 2

x = 6

4 0
3 years ago
ANSWER ASAP PLEASE & SHOW UR WORK!!!
Lina20 [59]

Answer:

x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}

Step-by-step explanation:

<u>Biquadratic Equations</u>

Solve:

x^4 + 3x^2 - 18 = 0

The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.

Solving such equations requires to express the equation as a second-degree equation with x^2 as the variable.

Rewriting the equation:

(x^2)^2 + 3(x^2) - 18 = 0

The quadratic equation can be factored as:

(x^2+6)(x^2-3)=0

It leads to two equations:

x^2+6=0

x^2-3=0

The first equation has imaginary roots. Solving for x:

x^2=-6

x=\pm\sqrt{-6}

x_1=\mathbf{i}\sqrt{6}

x_2=-\mathbf{i}\sqrt{6}

Where

\mathbf{i}=\sqrt{-1}

The second equation has two real roots:

x^2-3=0

x^2=3

x=\pm\sqrt{3}

x_3=\sqrt{3}

x_4=-\sqrt{3}

The roots are:

\mathbf{x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}}

3 0
3 years ago
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