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sergey [27]
4 years ago
7

6 friends share 5 meat pies each friend first eats half of a meat pie how much more meat pies does each friend need to eat to fi

nish all the meat pies and share them equally draw a quick picture to solve
Mathematics
2 answers:
Sphinxa [80]4 years ago
8 0
6 friends share 5 meat pies...
each friend eats half a pie.....6 * 1/2 = 6/2 = 3 pies eaten
so now there r 2 pies left
2/6 = 1/3.....so each friend has to eat 1/3 of a pie
mylen [45]4 years ago
4 0
First, write the number of meat pies in the form of a fraction with the denominator of 2 to separate it into halves.
5/1 = 10/2
There are 10 halves.
If 6 people each eat 1 half, this can be shown by 10/2 - 6/2, which equals 4/2.
So there are 4 halves remaining.
If the friends want to share them equally, they'll need to each eat less than a half. This is because there are 6 people and only 2 meat pies left.
To find how much each person can eat, divide the number of meat pies by the number of people.
2 / 6 = 0.33, or 1/3.
So each person can eat 1/3 of the remaining meat pies to share it equally.
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Find the equation of the line specified.<br> The slope is 7, and it passes through ( 8, 6).
STALIN [3.7K]

Answer:

The answer is A

Step-by-step explanation:

Given that the equation of line is y = mx + c and the slope is 7 :

y = 7x + c

By substituting the coordinate(8,6) into the equation, in order to find the value of c:

6 = 7(8) + c

6 = 56 + c

c = 6 - 56

= -50

y = 7x - 50

(Hope this can help)

6 0
3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
The order for points only matter when naming a ..?
Gnoma [55]

Answer:

Co-ordinate (x, y)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve this problem using substitution
Sergeeva-Olga [200]
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(x=y-8) & (y=x-8)

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6 0
3 years ago
Please solve each of the following by factoring!
Oxana [17]

Answer:

see explanation

Step-by-step explanation:

(a)

x² - 36 = 0 ← is a difference of squares and factors as

(x - 6)(x + 6) = 0

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 6 = 0 ⇒ x = 6

(b)

x² - 5x + 4 = 0

consider the product of the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

(x - 1)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 4 = 0 ⇒ x = 4

(c)

x² - 2x = 3 ( subtract 3 from both sides )

x² - 2x - 3 = 0 ← in standard form

consider the product of the factors of the constant term (- 3) which sum to give the coefficient of the x- term (- 2)

the factors are + 1 and - 3 , since

1 × - 3 = - 3 and 1 - 3 = - 2 , then

(x + 1)(x - 3) = 0 ← in factored form

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 3 = 0 ⇒ x = 3

(d)

6x² - 11x - 10 = 0

consider the product of the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 6 × - 10 = - 60 and sum = - 11

the factors are + 4 and - 15

use these factors to split the x- term

6x² + 4x - 15x - 10 = 0 ( factor the first/second and third/fourth terms )

2x(3x + 2) - 5(3x + 2) = 0 ← factor out (3x + 2) from each term

(3x + 2)(2x - 5) = 0

equate each factor to zero and solve for x

3x + 2 = 0 ⇒ 3x = - 2 ⇒ x = - \frac{2}{3}

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

6 0
2 years ago
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