Step-by-step explanation:
explained in the photo
Answer:
BA = 25π,
LA = 25√2π,
TA = 25π + 25√2π,
V = 41 and 2 / 3π
Step-by-step explanation:
We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,
( Height = 5 inches = Radius
______
Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "
- Base Area = 25π
______
The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula,
-
- Lateral Area = 25√2π
______
And the surface area is the base area + lateral area -
- Surface Area
______
The volume of a cone is 1 / 3rd that of a cylinder, with a simple formula of Base * height. Therefore, we can conclude the following -
- Volume = 41 and 2 / 3π
Answer:
Step-by-step explanation:
walks 3 miles in=45 min
1 mile in=45/3=15 minutes
26 miles=26×15=390 min.=6hrs 30 minutes
Answer:
a triangle with two equal sides
Step-by-step explanation:
Answer:
![\large\boxed{x=35^o}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%3D35%5Eo%7D)
Step-by-step explanation:
We have the equation:
![56^o+y+51^o=180^o\\\\(56^o+51^o)+y=180^o\\\\107^o+y=180^o\qquad\text{subtract}\ 107^o\ \text{from both sides}\\\\y=73^o\\\\\text{We know: the sum of the measures of the angles of the triangle}\\\text{is equal to}\ 180^o.\\\\\text{Therefore we have the equation:}\\\\x+y+72^o=180^o\qquad\text{put the value of}\ y\\\\x+73^o+72^o=180^o\\\\x+145^o=180^o\qquad\text{subtract}\ 145^o\ \text{from both sides}\\\\x=35^o](https://tex.z-dn.net/?f=56%5Eo%2By%2B51%5Eo%3D180%5Eo%5C%5C%5C%5C%2856%5Eo%2B51%5Eo%29%2By%3D180%5Eo%5C%5C%5C%5C107%5Eo%2By%3D180%5Eo%5Cqquad%5Ctext%7Bsubtract%7D%5C%20107%5Eo%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5C%5C%5C%5Cy%3D73%5Eo%5C%5C%5C%5C%5Ctext%7BWe%20know%3A%20the%20sum%20of%20the%20measures%20of%20the%20angles%20of%20the%20triangle%7D%5C%5C%5Ctext%7Bis%20equal%20to%7D%5C%20180%5Eo.%5C%5C%5C%5C%5Ctext%7BTherefore%20we%20have%20the%20equation%3A%7D%5C%5C%5C%5Cx%2By%2B72%5Eo%3D180%5Eo%5Cqquad%5Ctext%7Bput%20the%20value%20of%7D%5C%20y%5C%5C%5C%5Cx%2B73%5Eo%2B72%5Eo%3D180%5Eo%5C%5C%5C%5Cx%2B145%5Eo%3D180%5Eo%5Cqquad%5Ctext%7Bsubtract%7D%5C%20145%5Eo%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5C%5C%5C%5Cx%3D35%5Eo)