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Savatey [412]
3 years ago
9

If you know the number of yards for a measurement, you can change that measure to meters by multiplying the number of yards by 0

.9144 **Please Answer all 3**
1) Write a function rule that relates meters to yards.

2) How many meters are equivalent to 7,200 yards? Round the answer to the nearest hundredth, if necessary.

3) How many yards are equivalent to 2,500 meters? Round to the answer to the nearest hundredth, if necessary.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0
Question 1)

Let "y" denotes the number of yards and "m" denotes the number of meters. According to the give statement, measurement in yards can be changed to measurement in meters by multiplying the measure in yards by 0.9144.

So,

Measure in Meter = 0.9144 x Measure in Yards
m = 0.9144y

Question 2)

We are to convert 7200 yards into meters. Using the values in above equation we can write:

m = 0.9144 x 7200
m = 6583.68 meters

This means 7200 yards are equivalent to 6583.68 meters..

Question 3)

We are to convert 2500 meters to yards.
Using the value in above equation, we get:

2500=0.9144y
⇒
y = 2500/0.9144
y = 2734.03 yards

So this means 2500 meters are equivalent to 2734.03 yards.
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the size of the second application is 3.45 MB less than he first application. What is the size of the second application
mr_godi [17]

The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

<h3>Equation</h3>

Let

  • Size of the first application = x

  • Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

= 293.55 MB

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6 0
1 year ago
Somebody solve this plzz
mash [69]

Answer:

Not a function

Step-by-step explanation:

If you use the line/ pencil test ***I think that's what it's called...

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8 0
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

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3 years ago
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3 0
2 years ago
Read 2 more answers
a company owns two dealerships, both of which sell cars and trucks. the first dealership sells a total of 164 cars and trucks. t
OLEGan [10]

Answer:

294 cars.

Step-by-step explanation:

Let x be the number of cars and y be the number of trucks.

We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

x+y=164...(1)

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.

Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

2x+\frac{y}{2}=229...(2)

We can see that total number of cars sold on two dealerships will be x+2x=3x.

We will use substitution method to solve for x. From equation (1) we will get,

y=164-x

Substituting this value in equation (2) we will get,

2x+\frac{164-x}{2}=229

Now let us have a common denominator.

\frac{4x}{2}+\frac{164-x}{2}=229

\frac{4x+164-x}{2}=229

Upon multiplying both sides of our equation by 2 we will get,

2\times \frac{4x+164-x}{2}=2\times 229

4x+164-x=458

4x+164-164-x=458-164

4x-x=458-164

3x=294

Therefore, the total number of cars sold by two dealerships is 294.

7 0
3 years ago
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