Ask question

Ask question

All categories

3 years ago

9

Need an answer TODAY! Please only give correct and clean answers to this question, I will give Brainliest Answer if you do.

1 answer:

yan [13]3 years ago

5 0

A. When you equalize two equations, geometrically you are trying to find the intersection point of them, i.e. find the common point of them. So the x coordinate of the intersection point is basically the solution.

B. You can simply plug in numbers from -3 to 3 and list the values by yourself.

C. Graphically, draw each equation, and find the x coordinate of the intersection point.

FYI, the solution is x = 1/3

You might be interested in

A $70 jacket is on sale for 20% off. Each of the following strategies could correctly be used to find the amount of the discount

liraira [26]

Answer:

divide $70 by 0.2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the smallest power of 10that would exceed 999999999991

lozanna [386]

10^12

I hope that helps.

8 0

3 years ago

Can somebody help me please !?

r-ruslan [8.4K]

Answer:

option 4) x = 14 y = 7

Step-by-step explanation:

We are given a side angle and a side length so we can use trigonometry to find the solution

To find x we can use sine because the given side length is opposite to the angle so,

sin(60) = $\frac{7\sqrt{3} }{x}$

solve for x and you get 14 (make sure you check that your calculator is in degrees)

for either use Pythagorean theorem or remove sine by tangent.

4 0

3 years ago

What is the value of this expression when x=2 and y=-4? -3(x-y)2

Llana [10]

Answer:

-108

Step-by-step explanation:

$- 3 \times { (2 - ( - 4)) }^{2} = \\ - 3 \times ( {2 + 4})^{2} = \\ - 3 \times 36 = - 108$

4 0

2 years ago

Read 2 more answers

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago