What+is+the+slope+of.the+liine+of+the+passng+through+point+(0,-5)and+(4,2)

A bag contains 6 red marbles, 10 white marbles, and 7 blue marbles. You draw 4 marbles out at random, without replacement. What

Lapatulllka [165]

Answer:

3/1771

Step-by-step explanation:

Probability is the chance or likelihood that an event will occur.

Probability = expected outcome/total outcome

Total outcome = total number of marbles

Total outcome = 6+7+10 = 23marbles

If four marbles are drawn, the probability that they are all red is expressed as;

Pr(picking the first red marble) = 6/23

Since it is without replacement, the total marble becomes 22

Pr(picking the second) = 5/22

Pr(picking the third marbles = 4/21

Pr(picking the 4th marble) = 3/20

Note that the number of red marbles keep reducing and the total marble keep reducing as well.

Pr(picking the 4marbles) = 6/23×5/22×4/21×3/20 (we multiplied because or is an independent events)

Pr(picking the 4marbles) = 360/212520

Pr(picking 4 red marbles) = 72/42504 =36/21,252

= 9/5313

= 3/1771

Hence the probability of picking 4 marbles at random without replacement is 3/1771

4 0

3 years ago

How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i

zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

$\dbinom 31 \dbinom 32 = 3\cdot3 = 9$

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

$\dbinom 33 \dbinom 30 = 1\cdot1 = 1$

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

$\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}$

where we use the binomial identity

$\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n$

3 0

1 year ago

GUYS PLEASE HELP DUE SOONNN

jek_recluse [69]

Answer: -1 1/2 to -1: -1 1/3 and -5/4

-1 to -1/2: -2/3, -3/4, -6/7, -5/6

-1/2 to 0: -1/3 and -3/8

0 to 1/2: 1/5, 1/10, 3/12, 3/8, 3/7, 1/3

1/2 to 1: 4/5, 6/10, 7/8, 7/9, 3/4, 8/10

1 to 1 1/2: 1 5/12, 9/8

Step-by-step explanation:

4 0

2 years ago

1) Refer back to Lesson 2, Part A. Assume that the average shoulder width of the people in the line was 1.325 feet. How long wou

igor_vitrenko [27]

Answer:

13,250,000 feet or 13.25 million feet

Step-by-step explanation:

Each person in the line has a shoulder width of 1.325 feet.

For each person, there is a width of 1.325 ft. There are 10 million people.

Since:

10 million = 10,000,000

The total length must be:

$1.325 * 10,000,000$

$1.325 * 10,000,000 = 13,250,000$

Answer: 13,250,000 feet or 13.25 million feet

4 0

2 years ago

If a point is originally located at (2,9) and is translated 4 units to the right and 7 units up, what would its new

aliina [53]

Given:

The point is (2,9).

It is translated 4 units to the right and 7 units up.

To find:

The coordinates of new point.

Solution:

The point is translated 4 units to the right and 7 units up. So, the rule of translation is

$(x,y)\to (x+4,y+7)$

The point is (2,9). Using the above rule, we get

$(2,9)\to (2+4,9+7)$

$(2,9)\to (6,16)$

Therefore, the coordinates of new points are (6,16).

5 0

2 years ago