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JulsSmile [24]
3 years ago
6

How do extraneous solutions arise from radical equations?

Mathematics
2 answers:
Blababa [14]3 years ago
5 0
In general, extraneous solutions arise<span> when we perform non-invertible operations on both sides of an </span>equation<span>. (That is, they sometimes </span>arise, but not always.) ... Solvingequations<span> involving square roots involves squaring both sides of an</span>equation<span>. I hope that this helps you out, Have a wonderful day!!</span>
eduard3 years ago
3 0
In general, extraneous solutions arise<span> when we perform non-invertible operations on both sides of an </span>equation
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3 years ago
Please answer correctly !!!!!!!!!!!!!! Will Mark Brianliest !!!!!!!!!!!!!!!!!!!
alexgriva [62]

Answer:

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Step-by-step explanation:

well from the theorem we have

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well if you notice they are the same only that in my way the x is in the numerator which means it will be far easier to know it's value :)

so

\frac{15}{3}=\frac{x}{6}\\\\5=\frac{x}{6}\\\\6[5]=6[\frac{x}{6}]\\\\30=x

8 0
3 years ago
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aniked [119]

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Step-by-step explanation:

7 0
3 years ago
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Likurg_2 [28]

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Solution:

y = 2|-2 + 1|

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7 0
3 years ago
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Sladkaya [172]
Step-By-Step starts
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