Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
4y ≥ 3x + 2
Plugging in the values in the options, then the required values are when x = 6 and y = 5, then
4(5) ≥ 3(6) + 2
20 ≥ 18 + 2
20 ≥ 20
Answer:
Comparing each pair of lines,
AB and EF,
BC and FG,
CD and GH,
DA and HE.
For, AB and EF,
If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.
Also, we can use the formula, for the distance between two points on a coordinate plane,
,
As we can see in the image,
A = (-1, 1),
B = (-3, 2),
C = (-4, 4),
D = (-2, 6),
E = (2, 0),
F = (4, 1),
G = (5, 3),
H = (3, 5),
Solving using the formula,
AB = EF = √5,
BC = FG = √5,
CD = GH = √8,
DA = HE = √26,
Therefore, the length of all the sides of the polygon are the same,
Hence, the two figures are congruent.
Step-by-step explanation: