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d1i1m1o1n [39]
3 years ago
13

Granger walks 2 1/5 miles in 2/3 an hour at a constant speed.

Mathematics
1 answer:
Lorico [155]3 years ago
4 0
She walks 3 3/10 mph
In 1/3 an hour she walks 2 1/5 : 2 = 11/10
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Whats the inverse function of d(t)=70t
Charra [1.4K]

Answer:

d^-1(t)=t/70

Step-by-step explanation:

8 0
3 years ago
verify that the fucntion satisfies the three hypotheses of rolles theorem on the given interval . then find all numbers c that s
Ghella [55]

The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:

<span><span>x1 </span>= 0.42801</span>

<span><span>x2 </span>= −1.51414</span>

<span><span>x3 </span>= 3.08613</span>


x1 and x2 are in the desired interval [-2, 2]

f'(x) = 3x^2 - 4x - 4

so we have:

3x^2 - 4x - 4 = 0

<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6

x_1 = -4/6 = -0.66

x_ 2 = 2

According to Rolle's theorem, we have one point in between:

x1 = 0.42801 and x2 = −1.51414

where f'(x) = 0, and that is <span>x_1 = -0.66</span>

so we see that Rolle's theorem holds in our function.

4 0
3 years ago
if two positive integers P and Q can be expressed as p = a b square and q equals A cube B where A and B being prime numbers then
vodka [1.7K]
P = ab^2
q = a^3 b

p = a * b * b
q = a*a*a * b

Pairing the duplicates we have LCM = a*a*a*b*b  = a^3 b^2 answer
4 0
3 years ago
the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t
777dan777 [17]

Answer:

  • ratio: 2/3
  • sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

  an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

  a2 = a1·r^(2-1) = a1·r

  a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

  a4/a2 = (a1·r^3)/(a1·r) = r^2 = 8/18 = 4/9

Then r is ...

  r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

  a2 = 18 = a1·(2/3)

  a1 = (3/2)·18 = 27

__

The sum of the first 6 terms is ...

  Sn = a1·(r^n -1)/(r -1)

  S6 = 27·((2/3)^6 -1)/(2/3 -1)

  S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

  27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0
3 years ago
53 pts! which of the following is equal to g(x)?
ziro4ka [17]

Answer:

B is the correct answer, as x - 2 in the exponent would move the graph to the right 2.

7 0
3 years ago
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