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3 years ago

Which of the following numbers is classified as an irrational number?

Mathematics

1 answer:

Troyanec [42]3 years ago

4 0

A. square root of 72 because it is a non repeating decimal

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sarah works at a clothing store. Her weekly salary is $250 plus%4 commision on her sales.Last week she sold $ 2,500 worth of clo

creativ13 [48]

Answer:

80,000

Step-by-step explanation:

I hope this helps:)

3 0

3 years ago

What is the height of a cylinder with a volume of 1,899.7 cubic inches and a radius of 11 inches?

FrozenT [24]

Not 100% sure.

Height = 37.81inches

8 0

3 years ago

Read 2 more answers

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

3 years ago

Two cakes were cut into 8 slices iate 1/8 of the carrot cake . Iate 1/2 of the carrot cake .Me ate 1 slice of each. I ate three

FromTheMoon [43]

Answer:

There are 6 slices left.

Step-by-step explanation:

The remaining slices are:

Carrot Cake

$x = \left(\frac{8}{8} -\frac{1}{8} -\frac{4}{8} -\frac{1}{8} \right)\cdot 8$

$x = 2$

Chocolate Cake

$y = \left(\frac{8}{8} - \frac{1}{8} - \frac{3}{8} \right)\cdot 8$

$y = 4$

There are 6 slices left.

7 0

3 years ago

Is the data point, P, an outlier, an influential point, both, or neither?

telo118 [61]

I'd say an outlier. P is separated noticably from the other points and would not considerably affect the slope of the line

8 0

3 years ago

Read 2 more answers