Answer:
<u>Fred.</u>
Started hang gliding at a height of 700 ft and descends 15 feet every seconds
<u>Gene</u>
Started hang gliding at a height of 575 ft and descends 10 feet every seconds
Step-by-step explanation:
The function that models Fred's hang gliding is 
The initial value is 700 feet. This Fred was 700 feet above see level before he starts descending.
The rate of descent is -15 ft/s. This means Fred descends 15 feet in one second.
From the table the initial height is 575 ft. This means Gene was 575 feet above sea-level at the beginning of the hang gliding.
The rate of descent is 
ft/s.
This means that in every seconds, Gene descends 10 feet.
Answer: 55.5 (A.)
Step-by-step explanation:
Since angle A = 29 and angle B = 41, angle C must be equal to 110
180 = m<A + m<B + m<C
180 = 29 +41 + m<C
180 = 70 + m<C
110 = m<C
Therefore, side c must be the longest, side b must be the second longest, and side a must be the shortest.
Since side length a, angle A, and angle B are known, one can use the law of sines to solve for side b.
Law of Sines: sinA/a = sinB/b = sinC/c
sinA/a = sinB/b
sin29/41 = sin41/b
b(sin29/41) = sin41
b = 41(sin41)/(sin29)
b = 55.48
b = 55.5
Answer:
5/6
Step-by-step explanation:
1/3 + 1/2 is a simple addition fraction problem.
You'd find the LCM (lowest common denominator) which is 6. First, we'll take 1/3 which the denominator becomes 6. You see one side has been basically multiplied by 2, so you'd do it to both sides, giving us 2/6. Next, we do the same thing with 1/2. 2 -> 6 1 -> 3. 3/6. So finally, we have 3/6 + 2/6, which is 5/6.
Answer:
The rigth answer is, x = 1
Step-by-step explanation:
As:
f (x) = 3/4 x + 12
They separate the terms:
3/4 x = 12
Then, what you are multiplying happens to divide:
x = 12/1/3/4
Media are divided by means and ends with ends, and we have as a result that:
x = 3/3 = 1
Answer:
![[tex]4608\sqrt{3}](https://tex.z-dn.net/?f=%5Btex%5D4608%5Csqrt%7B3%7D)
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Step-by-step explanation:
1. 
2. 
<em>factoring 96</em>
<em>since 
</em>
3. 
<em>using exponent rule - 
</em>
<em> 
</em>
4. 
<em>doing some simple simplification and 
and 6=2*3</em>
5. 
<em>collecting the roots on one side and applying exponent rule</em>
6. 
<em>Applying exponents rule on all 
and 
</em>
<em>7. 
</em>
<em>combining all powers of 2</em>
8. 
<em>Simplifying</em>
9. 
10. 
11. 
