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JulijaS [17]
3 years ago
8

PLEASEEEEE HELP ME PLEASE WILL MAR AS BRANLIEST!!!!!!!!!!

Mathematics
1 answer:
mylen [45]3 years ago
3 0
That is right. Angle 2 to side 2 to angle 1 for both of them.The second triangle is just the first upside down.
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Which expression is equivalent to 15x+50
NNADVOKAT [17]
You would use distributive property 5x(2×+x)+50
5 0
3 years ago
What percent of 132 grams is 43.2 grams ?? ​
alexira [117]
The equation would be 43.2 divided by 132 which would give you .32 aka 32%
8 0
2 years ago
Just the answer please
nordsb [41]

Answer:b is the right choice hopefully dont be mad if it is wrong

Step-by-step explanation:

3 0
2 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
Mariana [72]

Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0
3 years ago
Sam wants to buy a CD player that costs $241. He has $25 that his uncle sent him for his birthday. He just started
Debora [2.8K]

Answer:

It will take Sam 18 weeks to save $241.

Step-by-step explanation:

The CD cost $241 then minus that by $25 and you get $216 than divide that by $12 because he gets that amount of money per week and then you get $18.

7 0
2 years ago
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