Here the time function is h(t) = [6 + 96t - 16t^2] feet.
The initial height of the ball is 6 feet. That's when t=0. h(0)=[6+0-0] ft = 6 ft.
At t=7 sec, h(t) = [6 + 96t - 16t^2] feet becomes
h(7 sec) = h(t) = [6 + 96(7) - 16(7)^2] feet This produces a large negative number (-106 ft), which in theory indicates that the ball has fallen to earth and burrowed 106 feet into the soil. Doesn't make sense.
Instead, let t=1 sec. Then h(1 sec) = h(t) = [6 + 96(1) - 16(1)^2] feet
=[6 + 96 -16] ft, or 86 ft.
One sec after the ball is thrown upward, it reaches a height of 86 feet. It continues to rise, slowing down, until it finally stops for an instant and then begins to fall towards earth.
Step-by-step explanation:
Cosine Ratio is the best tool to solve this problem.
cos38°=x/8
x =8*cos38°
x = 8*0.79
x = 6.32
Answer:
C
Step-by-step explanation:
Good Luck and I hope you do well :)
Answer:
1. The preimage and image are congruent
2. Any line segment connecting the corresponding points between the preimage and image is bisected by the line of reflection
3. Corresponding angles on the preimage and image are congruent
4. Corresponding points of the preimage and image are equidistant from the line of reflection.
Answer:
or 
Step-by-step explanation:
Step 1: Apply the fraction rule: 
Step 2: Cross-cancel common factor: 5
Step 3: Multiply fractions: 
Step 4: Multiply the numbers: 
Step 5: Multiply the numbers: 
Therefore, the answer is or in the simplified form;
