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4 years ago

−9x+2>18 AND 13x+15≤−4

Mathematics

2 answers:

Naddika [18.5K]4 years ago

6 0

Isolate the x. Do the opposite of PEMDAS.

-9x + 2 > 18

Subtract 2 from both sides

-9x + 2 (-2) > 18 (-2)

-9x > 18 - 2

-9x > 16

Isolate the x. Divide -9 from both sides. Note that when dividing by a negative number, you must flip the sign.

(-9x)/-9 > (16)/-9

x < 16/-9

x < -1.78 (rounded)

=====================================================================

13x + 15 ≤ -4

Do the same for this one. First, subtract 15 from both sides

13x + 15 (-15) ≤ -4 (-15)

13x ≤ - 19

Divide 13 from both sides

13x/13 ≤ -19/13

x ≤ -19/13

x ≤ ~-1.46 (rounded)

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hope this helps

fgiga [73]4 years ago

3 0

Answer:

The solution is x<-16/9

Step-by-step explanation:

1. Understanding the type of statement

We are given an AND statement. A certain x-value is a solution of the statement if it satisfies both of the inequalities.

Therefore, the solution of this statement is the intersection of the solutions of both inequalities. In other words, the overlap of the solutions of both inequalities is the solution of the statement.

2. Finding the solutions to the two inequalities

The solution of the first inequality, -9x+2>18, is x<-16/9.

-9x+2>18

-9x>16

x<-16/9

The solution of the second inequality, 13x+15≤-4, is x≤-19/13

3. The solution is x<-16/9

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