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alexgriva [62]
3 years ago
5

P(An B) = 2/3

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

8/9

Step-by-step explanation:

p(A/B) = p(A inersect B) / p(B)

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The table shows the results of a survey of students in two math classes.
qwelly [4]

P(more than 1 hour of TV | 6th period class) is  0.352.

<h3>What is the probability?</h3>

Probability determines the odds that a random event would happen. The odds of the random event happening lie between 0 and 1.

P(more than 1 hour of TV | 6th period class) = number of 6th period class students who watch tv for more than an hour / total number of students surveyed

12 / (12 + 9 + 5 + 8)

12 / 34 = 0.352

To learn more about probability, please check: brainly.com/question/13234031

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4 0
1 year ago
Use the equation v = StartFraction 10 Over p EndFraction to determine the pressure when the volume is 10 liters. A. 10 c. 100 b.
Galina-37 [17]

The value of the pressure is 1 when the value of volume is 10 liters, the correct option is D.

<h3>What is the pressure?</h3>

Pressure is defined as the physical force exerted on an object.

The force applied is perpendicular to the surface of objects per unit area.

Given

The equation is

\rm V=\dfrac{10}{p}

Where the v is the volume and p is the pressure.

The value of p when the value of volume v is 10 liters is;

\rm V=\dfrac{10}{p}\\\\\rm 10=\dfrac{10}{p}\\\\P = \dfrac{10}{10}\\\\P=1

Hence, the value of the pressure is 1.

To know more abour pressure click the link given below.

brainly.com/question/17799294

6 0
2 years ago
Use a table to write a funtion
Lady bird [3.3K]
I see no table sorry
8 0
3 years ago
A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol
bagirrra123 [75]

Answer:

a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message

c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message

d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message

Step-by-step explanation:

For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

25% of the incoming calls involve fax messages

This means that p = 0.25

25 incoming calls.

This means that n = 25

a. What is the probability that at most 4 of the calls involve a fax message?

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001

P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006

P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025

P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064

P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.001 + 0.006 + 0.025 + 0.064 + 0.118 = 0.214

0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b. What is the probability that exactly 4 of the calls involve a fax message?

P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118

0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.

c. What is the probability that at least 4 of the calls involve a fax message?

Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4). Then

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001

P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006

P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025

P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064

P(X

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.096 = 0.904

0.904 = 90.4% probability that at least 4 of the calls involve a fax message.

d. What is the probability that more than 4 of the calls involve a fax message?

Very similar to c.

P(X \leq 4) + P(X > 4) = 1

From a), P(X \leq 4) = 0.214)

Then

P(X > 4) = 1 - 0.214 = 0.786

0.786 = 78.6% probability that more than 4 of the calls involve a fax message

8 0
2 years ago
Let me know if anyone can answer this for me thank you.
Vladimir [108]
Let's calculate the slope of the A(3,1.5) and B(5, 2.5)

The formula of the slope m =(y₂-y₁)/(x₂-x₁)

m = (2.5 - 1.5)/(5 - 3)

m = (1)/(2) = 0.5
Aaron rate for mowing lawns is 0.5 Acre/Hour

8 0
3 years ago
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