Question

what is an equation of the line, in point slope form, that passes through the given point and has the given slope? point: (11/3); slope: 4/11

Answer 1

ANSWER

The required equation is,

$y - 3 = \frac{4}{11} (x - 11)$



EXPLANATION

The point given to us is,

$(11,3)$
and the slope is
$m = \frac{4}{11}$


We apply the point slope formula which is given as follows,

$y-y_1=m(x-x_1)$

We substitute the given point and the slope into the formula to obtain,

$y - 3 = \frac{4}{11} (x - 11)$
This is the equation of the given line in the point-slope form.

No need to simplify because it says point-slope form.

Answer 2

Y-3=4/11(x-11). Doing a problem like this is mostly memorizing point slope formula, by knowing y-y2=m(x-x1) you can just "plug" in 3 as your y1 and 11 as your x1 then finally 4/11 as your slope being y-3=4/11(x-11)