If you were to roll the dice one time what is the probability it will land on a 3?
2 answers:
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Answer:
The expected revenue of the tour operator is 985.
Step-by-step explanation:
There are two outcomes:
Either less than 21 tourists show up and the operator does not have to pay anything. Or 21 tourists show up and the operator has to repay 100.
Anyways, initially he gets the price of all the tickets sold. That is 21 each at 50, so .
Then, we need to find the probability that all of the 21 tourists show up. In this case, we have to subtract 100 from the revenue.
Each tourist has a 0.02 probability of not showing up. This means that each has a 1-0.02 = 0.98 probability of showing up. So the probability P that all 21 tourists show up is .
So, the expected revenue of the tour operator is
Rounded up, the expected revenue of the tour operator is 985.
Answer:
The blimp can carry 70 passengers
Step-by-step explanation:
Lets use the ratio method to solve this problem
∵ 1 cubic meter of helium can lift about 1.1 kg
∵ A blimp can carry as much as 2 x m³ of helium
By using the ratio method
→ m³ : kg
→ 1 : 1.1
→ 2 x : x
By using cross multiplication
∴ x × 1 = 1.1 × 2 x
∴ x = 2.2 x
∵ x represents the mass that can carried by the helium
∴ 2 x m³ of helium can lift 2.2 x
kg
∵ The mass of the blimp is 2.13 x kg
- Subtract the mass of the blimp from the mass that the given
amount of helium can lift to find the mass of the passengers
∴ The mass of the passengers = 2.2 x - 2.13 x
- Subtract 2.13 from 2.2 ⇒ 2.2 - 2.13 = 0.07
∴ The mass of the passengers = 0.07 x
∵ The average mass of a person with luggage is 10² kg
- Divide the mass of the passengers by the mass of the person
to find the number of the passengers
∴ The number of passengers = 0.07 x ÷ 10²
- Subtract the exponents of 10 to find the answer
∵ ÷ 10² =
= 10³
∴ The number of passengers = 0.07 x 10³
∴ The number of passengers = 0.07 × 1000
∴ The number of passengers = 70
The blimp can carry 70 passengers