Direct variation is written in the form y = k * x or x = y * k. And, inverse variation is written in the form y = k/x or x = y/k.
For the first problem, if we isolated the y, we would get:
4y = 3x - 1
y = (3/4)x - 1/4
This is written as y = mx + b, which isn’t the form of direct or inverse variation, so the answer is NEITHER.
For the second equation, we could divide by 2 on both sides to isolate x and see if it is in the correct form:
x = 4/y
This is inverse form, so the second question is INVERSE with a constant of variation as 4.
Answer:
a and b
Step-by-step explanation:
c times a equals b a ssspppppppspspspspspsp
Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
$8,029.91
Step-by-step explanation:
You have to use the exponential growth equation:
A=P(1+r)^t
Where A is the final amount, P is the initial amount, r is the rate of increase, and t is the time in years. So:
A=6,600(1+0.04)^5
(The rate has to be changed into a decimal)
Then, just plug this equation into a calculator (without the A= part, so just 6,600(1+0.04)^5) and you'll get the answer.
