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3 years ago

Please can someone help! I will mark you branliest!

Mathematics

1 answer:

wariber [46]3 years ago

3 0

27.47 should be the correct answer!

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-10 x-13

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Which of the following expressions are equivalent to 6 + (-4) - 5 ?

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Step-by-step explanation:

A and C gives same result....

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on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t

Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613 Eqn 1

1.75x+2.25y=1184.75 Eqn 2

Multiplying Eqn 1 by 1.75

$1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00$

Dividing both sides by 0.50

$\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224$

Putting y=224 in Eqn 1

$x+224=613\\x=613-224\\x=389\\$

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

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3 years ago

Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r

Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>

Since the degree of given polynomial is 4
Therefore it must have four roots.
Already given that the given polynomial has 1 positive real root and 1 negative real root .
Every polynomial with degree greater than 1 has atleast one imaginary root.

<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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