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Burka [1]
3 years ago
8

A lunch menu has 4 different sandwiches, 2 different soups, and 5 different drinks. How many different lunches consisting of a s

andwich, a soup, and a drink can you choose?
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0
To find out all of the possible combinations, just multiply the amount of each variable:

4*2*5 = 40

There are 40 different combinations consisting of a sandwich, soup, and drink.
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Approximate the square root of 12 to the nearest integer helppppppp!!!!!!!!
oee [108]

Answer:

3

Step-by-step explanation:

Well the square root of 12 is 3.464 and 12 squared is 144, and an intiger is a whole number no decimal or fraction. So round 3.464 to the nearest whole is 3. Hope this helps(:

3 0
3 years ago
6. Find the possible values of n in the inequality –3n < 81. A. n > –27 B. n < 27 C. n = –27 D. n = 27
evablogger [386]
-3n < 81...divide both sides by -3, change the inequality sign
n > -81/3
n > - 27 <==

** in an inequality, when dividing/multiplying by a negative number, the inequality sign changes
6 0
3 years ago
A shopper purchased 4 tables and 2 chairs for $200 and 2 tables and 7 chairs for $400. What is the cost of each table and each c
I am Lyosha [343]
4t+2c=200
2t+7c=400

I will solve for c in terms of t first
4t+2c=200
2c=200-4t
c=100-2t

Then I will substitute this in for c in the second equation to make it single variable
2t+7c=400
2t+7(100-2t)=400
2t+700-14t=400
300t=12
t=25 
Tables cost $25 each

Plug t back into one of the ORIGINAL equations to find the cost of chairs
4(25)+2c=200
100+2c=200
2c=100
c=50
Chairs cost $50 each

Hope this helps! :)


6 0
3 years ago
If 33 laptops cost 30,000, what proportion could be used to determine the cost of 11 laptops?
andre [41]

Answer:

30,00 divided by 33= 909.09 times 11=9,999.99  hope it helps you

Step-by-step explanation:

6 0
2 years ago
A six-sided fair die and an eight-sided fair die are rolled together. What is the probability of getting numbers whose sum is a
aalyn [17]
There are 48 possible outcomes in this situation, and of those outcomes, the ones whose sums are a multiple of three are;
12, 21, 15, 51, 24, 42, 33, 18, 27, 36, 63, 45, 54, 48, 57, and 66. So, that is 16 out of 48 possibilities, or 16/48, which simplifies to 1/3. Written as a percent, the probability of getting numbers whose sum is a multiple of three is 33.33%.

Hope this is helpful! :)
3 0
3 years ago
Read 2 more answers
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