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3 years ago

8

A lunch menu has 4 different sandwiches, 2 different soups, and 5 different drinks. How many different lunches consisting of a s

andwich, a soup, and a drink can you choose?

1 answer:

oksian1 [2.3K]3 years ago

5 0

To find out all of the possible combinations, just multiply the amount of each variable:

4*2*5 = 40

There are 40 different combinations consisting of a sandwich, soup, and drink.

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Two similar cylinders have surface areas of 24 cm² and 54 cm². The volume of the smaller cylinder is 16ñ cm³.

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Answer:54pid

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2 years ago

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riadik2000 [5.3K]

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Step-by-step explanation:

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3 years ago

I need help matching these

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Answer:

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3 years ago

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Choose the slope-intercept equation of the line that passes through the point (4, -6) and is parallel to y = - 1/2 x + 5. (3 poi

telo118 [61]

First, it is important to understand that parallel lines have the same slope. Therefore, based on the formula y=mx+b in which m represents slope and based on the equation y=-1/2x+5, the slope of the unknown line is also -1/2. Then, there are two different ways to solve this problem using different formulas.

The first method to find the unknown equation is easy but not widely known. We can use the point slope formula which is (y-y1)=m(x-x1) in which we can plug a point and slope to find the equation. When we plug in the values given, we get y+6=-1/2(x-4) or y+6 =-1/2x+2 which simplifies to y=-1/2x-4.

The other method is using the slope intercept form or y=mx+b. When we plug in our slope and our point, we get -6=-1/2*4+b or -6=-2+b so b must equal -4, therefore we have all the information we need to plug values into y=mx+b. When we plug in our slope and y-intercept, we get y=-1/2x-4 which is the answer.

I hope this helps!

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3 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

4 0

3 years ago