I say that it is A because I did this did this before
y = 6x - 4
Substitute the given x values to solve for y.
x = 1:
y = 6(1) - 4
y = 6 - 4
y = 2
1 = 2
x = 3:
y = 6(3) - 4
y = 18 - 4
y = 14
3 = 14
x = 10:
y = 6(10) - 4
y = 60 - 4
y = 56
10 = 56
x y
1 2
3 14
10 56
Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Answer:
x/y=1/4
Step-by-step explanation:
3x+2y=3y-2
3x=3y-2y-2
3x=y-2
y=3x+2
x+y=10
x+3x+2=10
4x+2=10
4x=10-2
4x=8
x=8/4
x=2
2+y=10
y=10-2
y=8
x/y=2/8=1/4
