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lesya [120]
3 years ago
12

Please help! Will give good rating.

Mathematics
1 answer:
Pavel [41]3 years ago
4 0
I think the mean would be the best because the data distribution is neither the mean nor median
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NEED HELP ASAP PLEASE PLEASE PLEASE​
nignag [31]

Answer:

tanθ=1.17

Step-by-step explanation:

please see the attachment below

8 0
3 years ago
A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those date
Anni [7]

Answer:

Confidence interval variance [21.297 ; 64.493]

Confidence interval standard deviation;

4.615, 8.031

Step-by-step explanation:

Given :

Variance, s² = 34.34

Standard deviation, s = 5.86

Sample size, n = 27

Degree of freedom, df = 27 - 1 = 26

Using the relation for the confidence interval :

[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]

From the chi distribition table :

X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844

Hence,

[34.34*26 / 41.923] ; [34.34*26 / 13.844]

[21.297 ; 64.493]

The 95% confidence interval for the population variance is :

21.297 < σ² < 64.493

Standard deviation is the square root of variance, hence,

The 95% confidence interval for the population standard deviation is :

4.615 < σ < 8.031

3 0
3 years ago
What is the coefficient of this expression?
WINSTONCH [101]

Answer:

4

Step-by-step explanation:

Define coefficient:

a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4xy).

Hope this helped.

6 0
3 years ago
5. Which step is included in the construction of inscribed polygons? (5 points)
RideAnS [48]

Answer:

Your answer is D

Step-by-step explanation:

Your welcome

5 0
3 years ago
The volume of a gas with a pressure of 1.2 atm increases from 1.0 L to 4.0 L. What is the final pressure of the gas, assuming co
salantis [7]

Answer:

(b) 0.30 atm

Step-by-step explanation:

Given data

Initial pressure= 1.2atm

Initial volume= 1.0L

Final volume= 4.0L

Final pressure= ???

Let us apply the gas formula to find the Final pressure

P1V1= P2V2

Substitute

1.2*1= x*4

Divide both sides by 4

1.2/4= x

x= 0.3atm

Hence the final pressure is 0.3 atm

5 0
3 years ago
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