Answer:
a. 125
b. 25/64
c. 0.25
d. 343
e. 49/4
f. 0.81
Step-by-step explanation:
multiply by the same number by the amount of times the power tells you
b. 5*5 = 25 8*8= 64
c. 5*5 = 25 0.5*0.5 = 0.25
d. 7*7*7 = 343
e. 7*7 = 49 2*2= 4
f. 9*9 = 81 0.9*0.9= 0.81
Answer:
<u><em>x=9</em></u>.
<em><u>perimeter=68</u></em>
<em><u>area=168</u></em>
Step-by-step explanation:
First find the side that has a exact number which would be the bottom 28cm then look at the opposite side (2x+10) in order to find x subtract 10 from 28 which gives you 18, now 2x means x multiplied by 2 so what multiplied by 2 = 18? 9 meaning <u><em>x=9</em></u>. Now you are going to want to plug 9 in to your short side (x-3) once you plug it in it should look like this 9-3 and 9-3=6 meaning the short side is 6cm. In order for you to find the perimeter you have to add the sides together so 28+28+6+6 wich <u><em>=68</em></u> and in order for you to find the area you have to multiply the length and the width so 28x6 which is <em><u>168</u></em>.
hope that helped :)
Answer:
Step-by-step explanation:
Area of a square = s²
s is the side length of the square
Given
s = 2^{7 1/2}
s = 2^15/2
Area = ( 2^15/2)²
Area = 2^15
Hence two area of the square is 2^15 inches
Answer:
-8,0
Step-by-step explanation:
From one end of a segment to the midpoint, it takes -6x to get to the midpoint. Based on that, you can go another 6 over the y graph and get -8 for x.
For y, the segment goes from 4 to 2 (a -2 over the x graph). you can infer then that the other end will be 0.
Answer:
Step-by-step explanation:
The max and min values exist where the derivative of the function is equal to 0. So we find the derivative:
Setting this equal to 0 and solving for x gives you the 2 values
x = .352 and -3.464
Now we need to find where the function is increasing and decreasing. I teach ,my students to make a table. The interval "starts" at negative infinity and goes up to positive infinity. So the intervals are
-∞ < x < -3.464 -3.464 < x < .352 .352 < x < ∞
Now choose any value within the interval and evaluate the derivative at that value. I chose -5 for the first test number, 0 for the second, and 1 for the third. Evaluating the derivative at -5 gives you a positive number, so the function is increasing from negative infinity to -3.464. Evaluating the derivative at 0 gives you a negative number, so the function is decreasing from -3.464 to .352. Evaluating the derivative at 1 gives you a positive number, so the function is increasing from .352 to positive infinity. That means that there is a min at the x value of .352. I guess we could round that to the tenths place and use .4 as our x value. Plug .4 into the function to get the y value at the min point.
f(.4) = -48.0
So the relative min of the function is located at (.4, -48.0)