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3 years ago

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While working on the roof of his house, John leans a 15 foot ladder against a second story window. If the distance on the ground

between the base of the ladder and the house is nine feet, at what height does the ladder reach the second story window? In your final answer, include all necessary calculations.

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

12 foot.

Step-by-step explanation:

Given that,

A ladder leans a 15 foot ladder against a second story window.

The distance on the ground between the base of the ladder and the house is 9 feet.

We need to find the height of the ladder. Let it is h.

If we consider a right angles triangle such that 15 foot is hypotenuse, 9 feet is base, then we need to find the perpendicular height of the triangle. Using Pythagoras theorem to find it.

$15^2=9^2+h^2\\\\h^2=15^2-9^2\\\\h^2=225-81\\\\h=12\ \text{foot}$

So, the height of the ladder that reaches the second story window is 12 foot.

Andrej [43]3 years ago

4 0

Answer:

12 foot.

Step-by-step explanation:

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sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

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The diagonals are perpendicular

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$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

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$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

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The slope of EG is undefined hence it is a vertical line.

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The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

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The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

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dexar [7]

Hope it helps

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<em>~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë</em>

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Answer:

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Step-by-step explanation:

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Substitute m = 6

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Substitute m = 6

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