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Sliva [168]
3 years ago
11

A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. Assume the amou

nt of garbage per bin is normally distributed. In a random sample of 40 bins, the sample mean amount is 52.8 pounds and the population standard deviation is 3.9 pounds. Construct 95% and 99% confidence intervals for the mean amount of garbage per bin for all bins in the city. Don't use 68/95/99.7 rule; instead use R to compute the quantities such as quantiles.
Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer: a) 51.592 b) 54.008 c) 51.213 d) 54.387

Step-by-step explanation:

a) lower limit of 95% interval

Lower limit = 52.8 - (1.96) (3.9/sqrt 40) = 51.592

b) upper limit of 95% interval

upper limit = 52.8 + (1.96) (3.9/sqrt 40) = 54.008

c) lower limit of 99% interval

Lower limit = 52.8 - (2.576) ( 3.9 / sqrt 40)= 51.213

d) upper limit of 99% interval

Upper limit = 52.8 + (2.576) ( 3.9 / sqrt 40) = 54.387

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