The first three terms of an arithmetic sequence are 3k-1, 4k+1, 6k-2. What is the value of k?
1 answer:
Answer:
k = 5
Step-by-step explanation:
First three terms of an AP are 3k-1, 4k+1, 6k-2.
First term is 3k-1
For an AP,
a₂-a₁=a₃-a₂
4k+1-(3k-1)=6k-2-(4k+1)
4k+1-3k+1=6k-2-4k-1
k+2=2k-3
Separating like terms,
k-2k=-3-2
-k=-5
k = 5
So, the value of k is 5.
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I thought it was the one above it but I think you are right tho
