Question

The first three terms of an arithmetic sequence are 3k-1, 4k+1, 6k-2. What is the value of k?​

Answer 1

Answer:

k = 5

Step-by-step explanation:

First three terms of an AP are 3k-1, 4k+1, 6k-2.

First term is 3k-1

For an AP,

a₂-a₁=a₃-a₂

4k+1-(3k-1)=6k-2-(4k+1)

4k+1-3k+1=6k-2-4k-1

k+2=2k-3

Separating like terms,

k-2k=-3-2

-k=-5

k = 5

So, the value of k is 5.