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harina [27]
3 years ago
5

The first three terms of an arithmetic sequence are 3k-1, 4k+1, 6k-2. What is the value of k?​

Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

k = 5

Step-by-step explanation:

First three terms of an AP are 3k-1, 4k+1, 6k-2.

First term is 3k-1

For an AP,

a₂-a₁=a₃-a₂

4k+1-(3k-1)=6k-2-(4k+1)

4k+1-3k+1=6k-2-4k-1

k+2=2k-3

Separating like terms,

k-2k=-3-2

-k=-5

k = 5

So, the value of k is 5.

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Solve for w<br> Simply as much as possible <br> -4w+7=-10w+37
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=============

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v = 6

Step-by-step explanation:

Solve for v:

-8 (8 v + 1) - 2 = -394

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