First we calculate the number
of moles of Cl2, that is:
moles Cl2 = 1.5*10^10
grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x <span>
So that based on stoichiometry, the number of moles of NaOH =
2x and that of H2 = x mol
mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg
= 1.68 metric tons
<span>mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg
= 0.042 metric tons.</span></span>
Answer:
condensation:The act or process of condensing or of being condensed pressureA pressing; a force applied to a surface.
temperature The state or condition of being tempered or moderated.
n:
Answer:
1.09 moles of NaOH
Explanation:
First of all, to calculate moles, you need to find the molar mass of NaOH.
Let us first find the molar mass of NaOH then.
Na = 23.0 amu
O = 16.0
H = 1.0
They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.
So do this.
23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.
Now use dimensional analysis to show your work
43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH
The grams cancel out.
43.5 / 40.0 = 1.0875
Use sig figs and round the answer to the nearest hundredths place.
1.0875 = 1.09
So the final answer is 1.09 moles of NaOH
Hope it helped!
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
