You missed a lot of details in your question, so when we have the complete question as the attached picture so, the answer would be:
when we have the value of Ka = 1.8 x 10^-5 so, we can use it to get the Pka value
by using this formula:
Pka = -㏒Ka
= -㏒(1.8 x 10^-5)
= 4.7
now, after we have got the Pka we need now to get moles of NaC2H3O2 and
moles of HC2H3O2:
when moles of NaOH = 0.015 moles
when moles NaC2H3O2 after adding NaOH
= initial mol NaC2H3O2 + mol NaOH
∴moles NaC2H3O2 = 0.1 + 0.015 = 0.115 moles
and moles HC2H3O2 after adding NaOH
= initial mol HC2H3O2 - mol NaOH
∴ moles HC2H3O2 = 0.1 - 0.015 = 0.085 moles
so, when we have moles [HC2H3O2] &[NaC2H3O2] so we can substitution its values in [A] &[HA] :
by using H-H equation we can get the PH:
when PH = Pka + ㏒[A]/[HA] PH = 4.7 + ㏒0.115/0.085
= 4.8
Nonpolar and hydrophobic
Phospholipid molecules have a polar and hydrophillic head, which consists of glycerol and phosphate ions. In a plasma membrane, this head points towards the hydrophillic environment outside of the cell. The tails, on the other hand, are hydrophobic and nonpolar, which means they do not allow water to pass through them.<span />
Molarity is defined by the number of moles of a substance dissolved in a number of liters in solution. 15,000 milliliters is equal to 15 liters, so
2.5/15 = 0.1666... M
The molarity of this solution would be 0.167.
Answer:
86.6 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 56.8 mL
Initial pressure (P₁) = 664 mmHg
Initial temperature (T₁) = 135 K
Final pressure (P₂) = 632 mmHg
Final temperature (T₂) = 196 K
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
664 × 56.8 / 135 = 632 × V₂ / 196
Cross multiply
135 × 632 × V₂ = 664 × 56.8 × 196
85320 × V₂ = 7392179.2
Divide both side by 85320
V₂ = 7392179.2 / 85320
V₂ = 86.6 mL
Therefore, the final volume of the gas is 86.6 mL
Answer:
2Mg + O₂ ⟶ 2MgO
Explanation:
Step 1. Start with the most complicated-looking formula (O₂?).
Put a 1 in front of it.
Mg + 1O₂ ⟶ MgO
Step 2. Balance O.
We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.
Mg + 1O₂ ⟶ 2MgO
Step 3. Balance Mg.
We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.
2Mg + 1O₂ ⟶ 2MgO
Every formula now has a coefficient. The equation should be balanced. Let’s check.
<u>Atom</u> <u>On the left</u> <u>On the righ</u>t
Mg 2 2
O 2 2
All atoms are balanced.
The balanced equation is
2Mg + O₂ ⟶ 2MgO