Answer:
After 18 hours, the amount of pure technetium that will be remaining is 12.5 grams
Explanation:
To solve the question, we note that the equation for half life is as follows;

Where:
N(t) = Quantity of the remaining substance = Required quantity
N₀ = Initial radioactive substance quantity = 100 g
t = Time duration = 18 hours
= Half life of the radioactive substance = 6 hours
Therefore, plugging in the values, we have;

Therefore, after 18 hours, the amount of pure technetium that will be remaining = 12.5 grams.
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Answer: Lithium fluoride is an inorganic compound with the chemical formula LiF.
Answer:
Explanation:
Carbon dioxide is the answer I think.
Hope it helps...
Answer: C(OCH2CH3)CHCClCH(CH)2
Explanation:
The structural formula for m-chlorophenyl ethyl ether is
C(OCH2CH3)CHCClCH(CH)2.
The structural formula shows the step-by-step linkages.