Question

What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3, and the temperature is 37.0 °C? ?G°\' for the reaction is –16.7 kJ/mol.

Answer 1

The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol

Further explanation

Given

Ratio of the concentrations of the products to the concentrations of the reactants is 22.3

Temperature = 37 C = 310 K

ΔG°=-16.7 kJ/mol

Required

the free energy change

Solution

Ratio of the concentration : equilbrium constant = K = 22.3

We can use Gibbs free energy :

ΔG = ΔG°+ RT ln K

R=8.314 .10⁻³ kJ/mol K

$\tt \Delta G=-16.7~kJ/mol+8.314.10^{-3}\times 310\times ln~22.3\\\\\Delta G=-8.698~kJ/mol$