Answer:
24x² -19x-35= 0
24x² -(40-21)x -35= 0
24x²-40x+21x-35=0
8x(3x-5) +7(3x-5)=0
(3x-5) (8x+7)=0
(Ax-5)(2Bx+C) = (3x-5) (8x+7)
Comparing them,
A = 3
B = 4
C= 7
AB-3C = (3×4) - 3(7) = 12-21 = -9
Answer: He ended up with about 1 pound less grapes
Step-by-step explanation:
2 bags of grapes weighing 5 and two-thirds pounds each will give a total weight of:
= 2 × 5 2/3
= 2 × 17/3
= 34/3
= 11 1/3 pounds
3 bags weighing 4 and one-fifth pounds each, will give a weight of:
= 3 × 4 1/5
= 3 × 21/5
= 63/5
= 12 3/5
He ended up buying lesser grapes. This was about 12 3/5 - 11 1/3 = 1 4/15 less. This means that he ended up with about 1 pound less grapes
The probability would be 9/12 or 3/4 in the lowest form
Answer:
Step-by-step explanation: for #1 its 6
for #2 it 12
#3 is 818
#4 is 423
#5 is 87
#6 is 500
hope this helped!
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
To learn more on quadratic equations: brainly.com/question/17177510
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