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katovenus [111]
3 years ago
10

Which statement reveals Kamkwamba’s ability to overcome obstacles? He didn’t care about getting an education and chose to leave

school. He felt bad for himself and gave up on learning after dropping out. He found a way to keep learning after he was forced to drop out.
Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

c

Step-by-step explanation:

Archy [21]3 years ago
4 0

Answer: C

Step-by-step explanation:

Took the test on edge

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Which integers are closest to 41
Jobisdone [24]

Answer:

the answer is 40

Step-by-step explanation:

because when you estimate 1 it will give you zero for example from 1234=0 56789 =1 so 1=to zero so the answer is 40

7 0
3 years ago
Please help me ………,,,
Sonbull [250]
I think it’s C
maybe it’s right
5 0
2 years ago
I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
NemiM [27]

Answer:

- (x - 1) {}^{2}  + 5

Step-by-step explanation:

F(x) is a transformation from h(x).

So our starting equation is

- (x - 1) {}^{2}  - 1

F(x) is also facing the same direction h(x) is so we dont have to reflect nothing across the x or y axis.

There isn't a vertical or horizontal stretch, compressions.

There isn't a horizontal shift as the x values stay in the same place.

There is a vertical shift. We can simply move h(x) up 6 units to get to f(x).

So our equation looks like.

- (x - 1) {}^{2}  + 5

8 0
2 years ago
3x + 2y = 12<br> y = x - 9
Lina20 [59]

Answer:

y=12/2

y=6

x=12/3

x=4

y= x-9

Y=4-9

y=5

6=5

6/5

1.2

5 0
2 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
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