If 4x+1 = 64, what is the value of x? A-3 B-4 C-2 D-5

Our family road trip to Yellowstone required driving approximately 610 miles. After 4 hours of driving we stopped for lunch and

Sonja [21]

Less then 10hrs but more then 9hrs not sure exactly

7 0

2 years ago

The distance between Johannesburg and Cape town is 1682km. If it took the bus 19:28 min to arrive at its destination calculate t

grandymaker [24]

Answer:

the average velocity is 86 km/h for the trip

Step-by-step explanation:

from the definition of average velocity

average velocity = distance covered / time required = 1682 km /(19 h + 28 min/60 min/h) = 86 km/h

therefore the average velocity is 86 km/h for the trip

7 0

2 years ago

Read 2 more answers

14. AMKL is an isosceles triangle with MK ML.If MK = 7x - 15, KL = 4x - 6, and ML = 10X - 12, find x and the measure of each sid

Alenkinab [10]

Answer:

You can do it! Sorry i can't help because your on a different level. Try your best!

Step-by-step explanation:

8 0

2 years ago

Solve for r in the diagram below. (x + 12) 100°

shusha [124]

Answer:

x = 34

Step-by-step explanation:

The sum of the three angles is 180 since they make a straight line

x+12 + 100 +x = 180

Combine like terms

2x+112=180

Subtract 112 from each side

2x+112-112= 180-112

2x = 68

Divide by 2

2x/2 =68/2

x = 34

7 0

2 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago