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3 years ago

If 4x+1 = 64, what is the value of x? A-3 B-4 C-2 D-5

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

None of these work, but the answer would be 15.75

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___ x 4 = 12<br> ___ x 5 = 20<br> ___ x 2 = 10

RideAnS [48]

Answer:

3 x 4 = 12

4 x 5 = 20

5 x 2 = 10

Step-by-step explanation:

3 + 3 + 3 + 3 = 12

3 four times equals 12

This is the same for the others

4 + 4 + 4 + 4 + 4 = 20

Four 5 times equals 20

4 0

3 years ago

What are the first three terms of a geometric sequence in which (picture below) and the common ratio is 5?

Marta_Voda [28]

Answer:

5, 10, 15

Step-by-step explanation:

the increase in the sequence is 5 so since it starts from 0 which you can find out because 25 is the 5th sequence and that means that +2*5 =25 . x=0

0+ 5 = sequence 1

0+ 5+5 = seq 2

0+5+5+5= seq 3

5 0

2 years ago

The cost of a long distance call is $1.25 for the

Vinil7 [7]

C

For first 3 minutes keep 1.25
Then for rest do 0.15(x-3)
Now add to get total cost

Mark brainliest please

8 0

3 years ago

Read 2 more answers

Classify the following triangle 120 degrees

Kipish [7]

Answer:

I think it is Obtuse.

Step-by-step explanation:

120 Degrees - Obtuse

6 0

3 years ago

Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)

Anna71 [15]

GIVEN:

$5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)$

remember:

$\sqrt{u} = {u}^{ \frac{1}{2} }$

And

${u}^{n} \times {u}^{m} = {u}^{n + m}$

SOLVE:

start by multiplying the factors:

$5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))$

simplify by combing like terms. Most terms subtract off, leaving:

$5( {u}^{6} - 1)$

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

$5( {u}^{3} - 1)( {u}^{3} + 1)$

I'm not exactly sure what form they want the answer in...

so taking the square root:

$\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }$

so my best answer is:

${5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }$
or the more factored form:

${5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }$

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!

7 0

3 years ago