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4 years ago

Combine the like terms in this expression: –3x + 2xy + 4y – xy + 2x – 11y A. 2xy + 15 B. –7xy C. –X+XY–7y D. 23X + y

Mathematics

1 answer:

s344n2d4d5 [400]4 years ago

7 0

Answer:

The correct option is C) –x + xy – 7y.

Step-by-step explanation:

Consider the provided expression.

Rearrange the expression so, that like terms comes together.

–3x + 2x + 2xy – xy + 4y – 11y

Now, add the like terms as shown below:

x(–3 + 2) + xy(2 – 1) + y(4 – 11)

Now, perform the operation inside the parentheses.

x(–1) + xy(1) + y(–7)

Open the parentheses.

–x + xy –7y

Now, compare with the provided options.

By comparison it can be concluded that the correct option is C).

Hence, the correct option is C) –x + xy – 7y.

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Step-by-step explanation:

The test statistic for difference between two population mean (when population standard deviation is known) is given by :

$z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}$

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$n_2$ = Size of second sample

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$\sigma_1$ = standard deviation for population 1.

$\sigma_2$ = standard deviation for population 2.

As per given , we have

$n_1=80$

$n_2=60$

$\overline{x}_1=\$6.75$

$\overline{x}_2=\$6.25$

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$\sigma_2=\$0.95$

Substitute these values in formula , we get

$z=\dfrac{6.75-6.25}{\sqrt{\dfrac{(1)^2}{80}+\dfrac{(0.95)^2}{60}}}$

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$z=\dfrac{0.50}{0.165956821694}$

$z=3.0128318613\approx3.01$

Hence, the value of the test statistic is <u>3.01</u>.

Hence, the correct option is c. 3.01 .

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