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Setler79 [48]
4 years ago
12

Combine the like terms in this expression: –3x + 2xy + 4y – xy + 2x – 11y A. 2xy + 15 B. –7xy C. –X+XY–7y D. 23X + y

Mathematics
1 answer:
s344n2d4d5 [400]4 years ago
7 0

Answer:

The correct option is C) –x + xy – 7y.

Step-by-step explanation:

Consider the provided expression.

Rearrange the expression so, that like terms comes together.

–3x + 2x + 2xy – xy + 4y – 11y

Now, add the like terms as shown below:

x(–3 + 2) + xy(2 – 1) + y(4 – 11)

Now, perform the operation inside the parentheses.

x(–1) + xy(1) + y(–7)

Open the parentheses.

–x + xy –7y

Now, compare with the provided options.

By comparison it can be concluded that the correct option is C).

Hence, the correct option is C) –x + xy – 7y.

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Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

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P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

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Step-by-step explanation:

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