0, 1, 2
sorry im not sure i think thsi may be missing some information
Answer:
1, 1.5, -1 1/5
Step-by-step explanation:
Answer:
1) Distribute 1.2 to 6.3 and -7x
2)Combine 3.5 and 7.56
3)Subtract 11.06 from both sides
Step-by-step explanation:
3.5 + 1.2(6.3 - 7x) = 9.38
Distribute 1.2 to 6.3 and -7x
3.5 + 1.2* 6.3 - 1.2 * 7x = 9.38
3.5 + 7.56 - 8.4x = 9.38
Combine 3.5 and 7.56
11.06 - 8.4x = 9.38
Subtract 11.06 from both sides
11.06 - 8.4x -11.06 = 9.38 - 11.06
-8.4x = -1.68
To find solution:
Divide both sides by (-8.4)
-8.4x/-8.4 = -1.68/-8.4
x = 0.02
Answer:
1968
Step-by-step explanation:
give me brainliest plsssss tysm
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
