3 years ago

Can someone please help me with this. I'm very bad at math.

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

2 5/6

Step-by-step explanation:

1.Rewriting our equation with parts separated

3+1/2-2/3

2.Solving the fraction parts

1/2-2/3=?

3.Find the LCD of 1/2 and 2/3 and rewrite to solve with the equivalent fractions.

LCD = 6

3/6-4/6=2 5/6

You might be interested in

Find the equation of the line with slope=6 and passing through (8,51). Write your equation in the form y=mx+b.

zzz [600]

Answer:

The answer to your question is: y = 6x + 3

Step-by-step explanation:

Data

slope = m = 6

A (8, 51)

Equation

y = mx + b

(y - y1) = m (x - x1)

(y - 51) = 6(x - 8)

y - 51 = 6x - 48

y = 6x - 48 + 51

y = 6x + 3

5 0

3 years ago

PLEASE HELP ASAP!!!!!!!!!!

ANTONII [103]

Answer: B

-3 x 4x = -12x
-3 x -0.50 = 1.50
-12x + 1.50

Hope this helped! :D

5 0

3 years ago

Read 2 more answers

Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]

Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

$A = \int\limits^a_b {f(x)} \, dx$

Applying to this question:

$A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx$

Then

$F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x$

$A = F(2) - F(-1)$

$F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}$

$F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}$

$A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42$

The area is 42 area units.

5 0

4 years ago

Please help with math homework show work<br><br>All of the questions

vagabundo [1.1K]

At least do number 3 so I can help with the rest. That ok with you?

3 0

3 years ago

Shoe Boxes A department store is selling its plastic shoe boxes for $1.50 off the

Firdavs [7]

T=4(r-1.5)

4(3.59-1.5)=t= 8.36 dolla

Enjoy.

7 0

3 years ago

Can someone please help me with this. I'm very bad at math.​

Can someone please help me with this. I'm very bad at math.