Answer:
7.9
Step-by-step explanation:
Multiply both sides of the equation by 11. This cancels out the fraction so 11 * 5/7 = x
lmk if I misunderstood the question or need to elaborate
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
All the triangles are isosceles meaning that they have to sides that are equal
Answer:
The circumference of the circle is 52π
Step-by-step explanation:
To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of a circle and we will clear the radius
a = area = 676π
r = radius
a = π * r²
we clear r
r = √(a/π)
now we replace the known values
r = √(676π/π)
r = √(676)
r = 26
now we use the formula to calculate the circumference of a circle
c = π * 2r
c = π * 2 * 26
c = 52π
The circumference of the circle is 52π
