Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
2/3
Step-by-step explanation:
Suppose x-6 is listed as a possible answer. That is zero if x = 6. So put x=6 into the original x^2 + 4x - 60 to get 6^2 + 4*6 - 60 = 36 + 24 -60 = 0. hence x-6 is a factor.
Answer (x-6)
on this hand :x-5 is not a factor, because plugging x=5 into does not work.
Answer:
x<(3b-5)/a
Step-by-step explanation:
Subtract 3b from both sides: -ax>5-3b
Divide by -a, when dividing/multiplying a negative you flip the </> sign: x<(3b-5)/a
Answer:
$ 1.32
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
- Cost of each Mott's Stick = $0.22 .
Now there are 6 sticks in an order . So the cost of six sticks will be ,
→ Cost = $ 0.22 × 6
→ Cost = $ 1.32
<h3>
Hence the cost of an order of sticks is $ 1.32 </h3>
