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3 years ago

If cos θ = 5/13, use the Pythagorean Identity to find sin θ.

1 answer:

6 0

Sin θ=sqrt(1-cos^2 θ)
sin θ=sqrt[1-(5/13)^2]
sin θ=sqrt[1-(5)^2/(13)^2]
sin θ=sqrt[1-25/169]
sin θ=sqrt[(169-25)/169]
sin θ=sqrt(144/169)
sin θ=sqrt(144)/sqrt(169)
sin θ=12/13

Answer: Second option 12/13

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Question 6 of 9 (3•8) • 1 = 3 • (8.1) O A. True B. False

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No, (false). The question I assume was: $(3*8)*1=3*(8.1)$

Step-by-step explanation:

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2. Multiple: The result of step No. 1: * 1 = 24 * 1 = 24

3. Conversion a decimal number to a fraction: 8.1 = $\frac{81}{10}$ = $\frac{81}{10}$

a) Write down the decimal 8.1 divided by 1: 8.1 = $\frac{81}{1}$

b) Multiply both top and bottom by 10 for every number after the

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$\frac{8.1}{1}$ = $\frac{81}{10}$

Note: $\frac{81}{10}$ is called a decimal fraction.

c) Simplify and reduce the fraction

$\frac{81}{10} = \frac{81*1}{10*1} = \frac{81}{10}$

4. Multiple: 3 * 8.1 = $\frac{3*81}{1*10}$ = $\frac{243}{10}$

Multiply both numerators and denominators. Result fraction keep to lowest

possible denominator GCD(243, 10) = 1. In the next intermediate step the

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In words - three multiplied by eighty-one tenths = two hundred forty-three

tenths.

5. Compare: The result of step No. 2 vs The result of step No. 4: = 24 vs $\frac{243}{10}$ = $\frac{24}{1}$ vs $\frac{243}{10}$ = $\frac{24*10}{1*10}$ vs $\frac{243}{10}$ = $\frac{240}{10}$ vs $\frac{243}{10}$ = 240 vs 243 = No

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3 years ago

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8_murik_8 [283]

Sum of 5 times z and 4 divided by two is 7.

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3 years ago

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