If cos θ = 5/13, use the Pythagorean Identity to find sin θ.

1 answer:

6 0

Sin θ=sqrt(1-cos^2 θ)
sin θ=sqrt[1-(5/13)^2]
sin θ=sqrt[1-(5)^2/(13)^2]
sin θ=sqrt[1-25/169]
sin θ=sqrt[(169-25)/169]
sin θ=sqrt(144/169)
sin θ=sqrt(144)/sqrt(169)
sin θ=12/13

Answer: Second option 12/13

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X=? Find x And explain plz

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<h2>Answer: (x = 1)</h2>

Step-by-step explanation:

We are given the equation 6(5x - 3) = 1/3(24x + 12), and we must find the value of x.

The first step is to distribute. Distribute the 6 to 5x and -3, and distribute 1/3 to 24x and 12. This give us the equation 30x - 18 = 8x + 4 to work with.

The next step is to get x by itself. In order to do this, subtract 18 from each side of the equation. This gives get's rid of the -18 and get's x by itself on one side of the equation and gives us the equation 30x = 8x +22.

Now that x is by itself on one side of the equation, get 22 by itself on the other side of the equation. The way to do this is to subtract 8x from each side. This gives us the equation 22x = 22.

Divide both sides by 22 and get the equation x = 1

$6(5x - 3) = \frac{1}{3} (24x + 12)$