If cos θ = 5/13, use the Pythagorean Identity to find sin θ.

1 answer:

6 0

Sin θ=sqrt(1-<span>cos^2 θ)
</span>sin θ=sqrt[1-(5/13)^2]
sin θ=sqrt[1-(5)^2/(13)^2]
sin θ=sqrt[1-25/169]
sin θ=sqrt[(169-25)/169]
sin θ=sqrt(144/169)
sin θ=sqrt(144)/sqrt(169)
sin θ=12/13

Answer: Second option 12/13

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