Answer:
20.9-26.2 = -5.3 to the left (or 5.3 to the right)
Answer:
a) Right 0≤p<π/2 and 3π/2<p≤2π
left π/2 ≤ p ≤3π/2
stopped p=π/2 and p=3π/2
b) 5.5cm and its final position (2π, 0)
c) 6.5cm
Step-by-step explanation:
we must find where the function becomes negative, positive and zero
(according to the graph)
the particle moves to the right where the function is positive
0≤p<π/2 and 3π/2<p≤2π , the particle moves to the left where the function is negative π/2 ≤ p ≤3π/2, and stopped p=π/2 and p=3π/2
s(t)=∫v(t)dt also s(t) = 5sin(t)
(according to the graph 2)
The displacement of the particle is 5.5 and its final position
(2π, 0)
The total displacement of the particle is 6.5
The first 4 on the left has a value of 400. The next 4 has a value of 40. The first 4 is in the hundreds place and the second 4 is in the 10's place.
Answer:
Step-by-step explanation:
"The graph of f(x) is a horizontal compression of the graph of the parent function" is true; the graph will appear to be narrower than that of y = |x|. I would prefer to state "the graph of f(x) exhibits vertical stretching of the original (parent) function graph."
Answer: x= 3 y=0
x= 0 y=4
Step-by-step explanation: Because the x value is the first number like (3,0) in this 3 is the first number. Y is the second. HOPE IT HELPS!