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4 years ago

How do you convert 2.314 (14 repeating) as a fraction?

Mathematics

1 answer:

Katarina [22]4 years ago

7 0

Answer:

You multiply it by 1000. If you're talking about converting decimals to fractions.

Step-by-step explanation:

2.314

2 is the whole number, you leave that alone for right now.

0.314 is the decimal part.

Rewrite the decimal with a denominator of 1.

$\frac{0.314}{1}$

Because this decimal goes all way to the thousandths place, you multiply the top and the bottom by 1,000.

$\frac{0.314}{1}$ ×1000= $\frac{314}{1000\\}$

Next you simplify divide the top and bottom by the GCF (greatest common factor) in this case 2.

$\frac{3.14}{1000}$ ÷2

= $\frac{157}{500}$

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write the equation of the line that passes throughout (-1,5) and has a slope of 3 in point-slope form

SpyIntel [72]

The point-slope form is:
$y - k = m(x-h)$

So, here, you just plug in values:
$y - 5 = 3(x+1)$

It would be + 1 because remember, the '-' sign just means the opposite of, not subtraction in this case. Also, m = slope.

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4 years ago

Gabriel wants to solve the equation 5 eights M equals 25 what steps should he do to get him by itself on one side of the equatio

Neporo4naja [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the Equation :

(5/8)m = 25

The first step to take with this kind of equation is to multiply both sides by the denominator, 8

5m/8 * 8 = 25 *8

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3 years ago

If (2i/2+i)-(3i/3+i)=a+bi, then a= A. 1/10 B. -10 C. 1/50 D. -1/10

Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

We need to find the value of a.

The LCM of (2+i) and (3+i) is (2+i)(3+i)

$=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}$

Now rationalize the denominator by multiplying by 5-5i/5-5i

$=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}$