Answer:
6 rad/s
Explanation:
In a spring the angular frequency is calculated as follows:
where 
is the angular frequency, 
is the mass of the object in this case 
, and 
is the constant of the spring.
To calculate the angular frequency, first we need to find the constant which is calculated as follows:
Where 
is the force: 
, and 
is the distance from the equilibrium position: 
.
Thus the spring constant:
And now we do have everything necessary to calculate the angular frequency:
the angular frequency of the oscillation is 6 rad/s
Newton's 2nd law of motion:
Force = (mass) x (acceleration)
Divide each side
by 'acceleration': Mass = (force) / (acceleration)
= (2,500 N) / (200 m/s²)
= 12.5 kg
Answer:
The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.
Explanation:
Given that,
Velocity = 270 m/s
Acceleration = 9.0g s
We need to calculate the altitude
Using formula of centripetal acceleration
Where, v = velocity
r = altitude
a = acceleration
Put the value into the formula
Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.
Answer:
1185 N
Explanation:
From Newton’s second law of motion,
F=ma where m= mass of motorcycle, a is acceleration of the motorcycle and F=Force
Net force acting on motorcycle 
is given by 
Where F is force acting on motorcycle and f is frictional force
Substituting F-f for
hence ma= F- f Substituting a with 3, m with 245Kg and f with 450N as provided
245*3= F- 450
F=245*3 +450= 1185 N
Answer:
750,000
Explanation:
I just looked it up on Google lol. You apparently multiple by 1000
Hope this helps :p
