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gizmo_the_mogwai [7]
3 years ago
10

The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by the expression v = (-5.15 multipli

ed by 107) t2 + (2.30 multiplied by 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
(b) Determine the length of time the bullet is accelerated.

(c) Find the speed at which the bullet leaves the barrel.

(d) What is the length of the barrel?
Physics
1 answer:
alisha [4.7K]3 years ago
3 0
I'm assuming you're in calculus based physics. I apologize if otherwise. Let's come up with equations for distance and acceleration as functions of time. From the definition of acceleration we know that<span>a=<span><span>dv</span><span>dt</span></span></span>Taking the derivative of v with respect to t yields<span>a=<span><span>dv</span><span>dt</span></span>=(−5.15∗107)∗2∗t+(2.30∗105)</span> From the definition of distance, we know that <span>v=<span><span>dx</span><span>dt</span></span>→dx=vdt</span>Integrating velocity yields<span>x=(−5.15∗107)∗<span>(<span><span>t3</span>3</span>)</span>+(2.30∗105)∗<span>(<span><span>t2</span>2</span>)</span>+<span>x0</span></span> where <span>x0</span> is the starting position. If acceleration is zero when the bullet leaves the barrel, we can use our equation for acceleration to determine the time the bullet is in the barrel. This is seen as<span>0=(−5.15∗107)∗2∗t+(2.30∗105)→t=<span><span>−(2.30∗105)</span><span>(−5.15∗107)</span></span></span> Knowing time, we can solve for the velocity as the bullet leaves the barrel by plugging time back into our given equation for velocity. The length of the barrel can be solved by plugging time back into our equation for distance and setting <span><span>x0</span>=0</span><span>.</span>
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Naddik [55]

Answer:

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4 0
3 years ago
A parallel plate capacitor with air between the plates has a potential difference of 71.0 V. Determine the potential difference
Gwar [14]

Answer:

15.8 V

Explanation:

The relationship between capacitance and potential difference across a capacitor is:

q=CV

where

q is the charge stored on the capacitor

C is the capacitance

V is the potential difference

Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.

Later, a dielectric material is inserted between the two plates, so the capacitance changes according to

C'=kC

where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,

q=C'V'

So we can combine the two equations:

CV=CV'\\CV=(kC)V'\\V'=\frac{V}{k}

and since we have

V = 71.0 V

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6 0
3 years ago
A pilot wishes to flt his planne to an airport north of his current location
Ann [662]

Answer:

Time = 2758.62 seconds

Explanation:

Given the following data;

Speed = 290 m/s

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To find the time;

Time = distance/speed

Time = 800000/290

Time = 2758.62 seconds

Therefore, it will take the pilot 2758.62 seconds to reach the airport.

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Brrunno [24]
Weight  = Mass * gravity

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