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3 years ago

What is the length x of a side of the small inner square? Drawing is enclosed in OS link.

1 answer:

5 0

So based on your question about the line A and B meet and the four lines are congruent to each other. The graph doesnt show any measurements so there is no exact value to the length of X. But you must consider that the lines are proportional to each other so it means that they are congruent.

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The tickets for the theater cost 7.50 each. Miles bought 4 of them and gave the cashier a fifty dollar bill. What was the cost o

Dahasolnce [82]

the cost of the tickets was 30$ . Change was 20$

5 0

3 years ago

14. The equation of the line that passes through the

KIM [24]

Answer:

5. y = -x

Step-by-step explanation:

First, you need to find the slope of the line.

$m = \frac{2 - (-3)}{-2 - 3} = \frac{5}{-5} = -1$

Now, using either point substitute into the point-slope form for a line:

$y - y_{1} = m(x - x_{1} )$

Using (-2,2) for $(x_{1} , y_{1} )$ we get y - 2 = -1(x +2)

y - 2 = -x - 2

y = -x

Answer 5 is the correct answer

3 0

3 years ago

Choose 3 ratios in simplest form. 3:9

Sonja [21]

Answer:

Step-by-step explanation:

1:3

6:18

9:27

are all equivlent ratios

7 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

1,3,5,7,9, 11, ……………………… is a sequence of odd numbers. Write down the 35th odd number.

Fiesta28 [93]

69 is the 35th odd number.

5 0

3 years ago

Read 2 more answers