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Harrizon [31]
3 years ago
11

5- Given the reaction

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

Explanation:

5)

Given data:

Mass of FeS₂ = 3.8 g

Mass of SO₂ = ?

Solution:

Chemical equation:

4FeS₂ + 11O₂      →      2Fe₂O₃ + 8SO₂

Number of moles of FeS₂:

Number of mole = mass / molar mass

Number of mole = 3.8 g / 119.98 g/mol

Number of moles = 0.03 mol

Now we will compare the moles of SO₂ with FeS₂.

                             FeS₂           :            SO₂

                                 4             :             8

                                0.03        :         8/4 ×0.03 = 0.06

Mass of SO₂:

Mass = number of moles × molar mass

Mass = 0.06 mol × 64.066 g/mol

Mass = 3.84 g

6)

Given data:

Mass of SO₃ form = ?

Mass of SO₂ react = 4.1 g

Solution:

Chemical equation:

2SO₂ + O₂   →    2SO₃

Number of moles of SO₂ :

Number of moles = mass/ molar mass

Number of moles = 4.1 g/ 64.066 g/mol

Number of moles = 0.064 mol

Now we will compare the moles of SO₃  with SO₂.

                        SO₂         :          SO₃

                          2            :           2

                      0.064        :        0.064

Mass of SO₃:

Mass = number of moles × molar mass

Mass = 0.064 mol × 80.066 g/mol

Mass = 5.12 g

7)

a)

Given data:

Mass of glucose = 10 g

Mass of CO₂ formed = ?

Mass of H₂O formed = ?

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂  →      6CO₂ + 6H₂O

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 10 g/ 180.156 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of sugar with each product.

                 C₆H₁₂O₆           :            CO₂

                      1                  :               6

                     0.06             :          6×0.06 = 0.36 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.36 mol × 44 g/mol

Mass = 15.84 g

                  C₆H₁₂O₆          :            H₂O

                      1                  :               6

                     0.06             :          6×0.06 = 0.36 mol

Mass of H₂O:

Mass = number of moles × molar mass

Mass = 0.36 mol × 18 g/mol

Mass = 6.48 g

b)

Number of moles of CO₂ = 0.36 mol

Number of moles of H₂O = 0.36 mol

Number of molecules of CO₂ = ?

Number of molecules of  H₂O = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ molecules of water

0.36 mol  × 6.022 × 10²³ molecules of water  / 1 mol

2.17 × 10²³ molecules of water

For CO₂:

1 mole = 6.022 × 10²³ molecules of CO₂

0.36 mol  × 6.022 × 10²³ molecules of CO₂  / 1 mol

2.17 × 10²³ molecules of CO₂

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What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the act
Basile [38]

Answer:

D) 7.5 grams

Explanation:

Hello,

In this case, since the percent yield is defined by:

Y=\frac{m^{actual}}{m^{theoretical}} *100\%

In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:

m^{actual}=\frac{Y*m^{theoretical}}{100\%}  =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g

Therefore the answer is D) 7.5 grams.

Best regards.

5 0
3 years ago
Calculate delta Gº for the following system:
Llana [10]

Answer:

ΔG = - 442.5  KJ/mol    

Explanation:

Data Given

delta H = -472 kJ/mol

delta S = -108 J/mol K

So,

delta S = -0.108 J/mol K

delta Gº = ?

Solution:

The answer will be calculated by the following equation for the Gibbs free energy

                    G = H - TS

Where

G = Gibbs free energy

H = enthalpy of a system (heat

T = temperature

S = entropy

So the change in the Gibbs free energy at constant temperature can be written as

                ΔG = ΔH - TΔS . . . . . . (1)

Where

ΔG = Change in Gibb’s free energy

ΔH = Change in enthalpy of a system

ΔS = Change in entropy

if system have standard temperature then

T = 273.15 K

Now,

put values in equation 1

                  ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)

                 ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)

                 ΔG = -472 kJ/mol + 29.5 KJ/mol

                 ΔG = - 442.5  KJ/mol          

7 0
3 years ago
This is the question
iragen [17]
None of these because it doesn’t make since
5 0
2 years ago
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This question is about acids and bases.
marusya05 [52]

Answer:

<em><u>OH-</u></em> is the correct answer

mark me brainst answer

7 0
3 years ago
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