Question

The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the actual yield of the reaction? A) 13 grams B) 120 grams C) 208 grams D) 7.5 grams

Answer 1

Answer:

D) 7.5 grams

Explanation:

Hello,

In this case, since the percent yield is defined by:

$Y=\frac{m^{actual}}{m^{theoretical}} *100\%$

In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:

$m^{actual}=\frac{Y*m^{theoretical}}{100\%} =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g$

Therefore the answer is D) 7.5 grams.

Best regards.