All categories

2 years ago

What is the prime factorization of 84 a) 2x2x3x7 b)2x3x7 c)2x3x3x7 d)2x2x3x3x7

Mathematics

2 answers:

e-lub [12.9K]2 years ago

6 0

A is the correct answer because if you times them all together it equals 84

AlexFokin [52]2 years ago

5 0

A) 2x2x3x7 should be the correct answer.

You might be interested in

K² = 76<br><br>What is the answer?

Dmitry_Shevchenko [17]

Answer:

k = 2 √ 19 , − 2 √ 19

Step-by-step explanation:

Take the root of both sides and solve.

3 0

2 years ago

Read 2 more answers

Find the area of the triangle. If necessary, round the answer to two decimal places.

bija089 [108]

If i used the correct numbers for the base and the height the area of the triangle would be 182

5 0

2 years ago

Read 2 more answers

Evaluate: 2xy^2-3xy-7 if x=-4and y=5

Margaret [11]

Answer:

-147

Step-by-step explanation:

-8 x 25 + 60 -7

5 0

2 years ago

Which value for x makes the sentence true?

marshall27 [118]

43/76

This is the answer

3 0

2 years ago

Read 2 more answers

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

2 years ago