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2 years ago

What happens to the surface area of a rectangular prism when each of the dimensions is doubled? (1 point) i?

1 answer:

5 0

The surface area will be 4 times the original size. Here is why: You are doubling each dimension, and area is a 2 dimensional measurement. Because of this whatever you are doing to the length of the side will happen 2 times. In this case it would be x2 x2 which equals 4. You can provide evident by using a cube. The surface area of a cube with side lengths of 1 would be 1 x 6=6 square inches. If you double the side length, it would be 4 x 6= 24 square inches.

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Kurt deposited money into his bank account every month. The amount of money he deposited in the first 5 months of 2014 is listed

Irina-Kira [14]

Answer:

that is the answer

Step-by-step explanation:

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2 years ago

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HACTEHA [7]

Answer:

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Step-by-step explanation:

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2 years ago

Simplify in fraction form<br> 60a+64≥80a−92

lukranit [14]

Answer:

a≤39/5

Step-by-steep explanation:

60a+64≥80a−92

Step 1: Subtract 80a from both sides.

60a+64≥80a−92

-80a -80a

−20a+64≥−92

Step 2: Subtract 64 from both sides.

−20a+64≥−92

-64 -64

−20a≥−156

Step 3: Divide both sides by -20.

−20a≥−156

a≤39/5

5 0

2 years ago

What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

2 years ago

Need help please !!!!!!

11Alexandr11 [23.1K]

A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is. $\sqrt{192}= \sqrt{64*3}= 8\sqrt{3}$ . $\sqrt{80}= \sqrt{16*5}=4 \sqrt{5}$ . $\sqrt{12288}= \sqrt{4096*3}=64 \sqrt{3}$ . The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same. In other words, we cannot add the square root of 4 to the square root of 5. They either both have to be 4 or they both have to be 5. So here's what we have thus far: $8 \sqrt{3}+4 \sqrt{5}+64 \sqrt{3}$ . We can add $8 \sqrt{3}$ and $64 \sqrt{3}$ to get $72 \sqrt{3}$ . That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.

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2 years ago