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3 years ago

How to write numbers in two other forms ? 6,007,200

1 answer:

5 0

<span>in words: six million, seven thousand two hundred or in scientific notation: 6.0072 x 106in expanded form: 6 000 000 + 0 + 0 + 7000 + 200 + 0 + 0</span>

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The first term of a geometric sequence is 3. The sum of the first two terms is 15 and the sum of the first 3 terms is 63. Deter

pav-90 [236]

63 is the common term. 3+12+48=63

8 0

3 years ago

HELP PLSSSS I will GIVE BRAINLYEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

hammer [34]

First we convert 3 5/6 to 21/6 by multiplying 3 to 6 and then adding 5 to it.

➡️ 3*6+5/6 = 21/6

Then to make it easier to add you convert 1/3 to 2/6 which is equal to 1/3.

➡️ 21/6 + 2/6 = 23/6

4 0

3 years ago

Consider the expansion of (x + 2y)^10. Determine the coefficients for the terms with the powers of x and y shown.

julsineya [31]

Answer with Step-by-step explanation:

We are given that an expression

$(x+2y)^{10}$

Binomial expansion o f $(x+y)^n$ is given by

= $nC_0 x^n+nC_1x^{n-1}y^1+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+... nC_n y^n$

a. We have to find the coefficient of $x^2y^8$

$(x+2y)^{10}=10C_0x^{10}+10C_1x^9(2y)+10C_2x^8(2y)^2+10C_3x^7(2y)^3+...+10C_{10}(2y)^{10}$

Term is $10C_8x^(2y)^8$

Coefficient = $10C_8\cdot 2^8$

b.Term in which $x^4y^6$ is $10C_6x^4(2y)^6$

Coefficient = $10C_4\cdot 2^6$

c.We have to find the coefficient of $x^5y^5$

Term is $10C_5x^5(2y)^5$

Coefficient = $10C_5\cdot 2^5$

7 0

3 years ago

Read 2 more answers

Craig has a building block in the shape of a rectangular pyramid. A net of which is shown below.

Alex787 [66]

Answer:

the answer is D: 294 sq. cm

Step-by-step explanation:

first you want to split the net into 4 triangles and 1 rectangle

a = 12 cm

b = 6 cm

d = 13 cm

calculate the surface area of the pyramid...

1st find the area of the rectangle base

Rectangle base area

b x a = (6 cm) (12 cm)

= 72 sq. cm

next find the area of the triangle on the left

Left triangle

1/2(b)(d) = 1/2 (6 cm)(13 cm)

= 1/2 (78 sq cm)

= 39 sq. cm

Since all the triangles are congruent (same), you will need to multiply by 2 to get the combined area of the triangle on the left and on the right.

Area of left & right triangles

= 2 (39 sq. cm)

= 78 sq. cm

Find the area of the triangle on the bottom

Bottom triangle area = 1/2 (a)(a)

= 1/2 (12 cm) (12 cm)

= 1/2 (144 sq. cm)

= 72 sq. cm

Since the bottom of the triangle is congruent to the top triangle, multiply that by 2 to get a combined area of the triangle on the bottom and top

Area of top & bottom triangles

2 (72 sq. cm) = 144 sq. cm

Finally...add the area of the 4 triangles to the area of the rectangular base

72 + 78 + 144 = 294 sq. cm

3 0

3 years ago

Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a

Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

3 0

2 years ago