Answer:
See the attached picture.
Explanation:
See the attached picture.
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
The total cost is $13.0
Explanation:
Five Star Retro Video rents VHS tapes and DVDs to the same connoisseurs who like to buy LP record albums. The store rents new videos for $3.00 a night, and oldies for $2.00 a night.
Write a program that the clerks at Five Star Retro Video can use to calculate the total charge for a customer's video rentals.
The program should prompt the user for the number of each type of video and output the total cost.
Question
Student presentation concepts from another source
Letitia - a step-by-step process of breaking down glucose into energy
Mana - repeating process of the steps of the cell division, going from interphase to division, and back to interphase.
Paul - a series of organisms that show similar characteristics and compare them to those that do not
Which best describes the SmartArt graphic layout each student should use?
Answer:
Letitia would use a process, Maria would use a cycle, and Paul would use a relationship.
Explanation:
Letita's assignment requires her to show how glucose can be broken down into energy, this requires a series of steps in s linear fashion, meaning it would be best suited to a process-style diagram.
Marta's project involves showing the steps of the cell cycle: the clue is in the name. This process is not linear, and instead repeats itself, meaning it fits to a cycle diagram (i.e. a circular diagram)
Paul is comparing and contrasting different organisms. Therefore, he should use a relationship diagram to show shared characteristics as well as features that differ.
