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NARA [144]
3 years ago
10

Several students are making presentations for a science class. The chart describes the concept that each student will present to

the class.
Which best describes the SmartArt graphic layout each student should use?

Letitia would use a hierarchy, Maria would use a cycle, and Paul would use a process.
Letitia would use a cycle, Maria would use a hierarchy, and Paul would use a relationship.
Letitia would use a process, Maria would use a cycle, and Paul would use a relationship.
Letitia would use a process, Maria would use a relationship, and Paul would use a hierarchy.
Computers and Technology
1 answer:
Sedbober [7]3 years ago
4 0

Question

Student presentation concepts from another source

Letitia - a step-by-step process of breaking down glucose into energy

Mana - repeating process of the steps of the cell division, going from interphase to division, and back to interphase.

Paul - a series of organisms that show similar characteristics and compare them to those that do not

Which best describes the SmartArt graphic layout each student should use?

Answer:

Letitia would use a process, Maria would use a cycle, and Paul would use a relationship.

Explanation:

Letita's assignment requires her to show how glucose can be broken down into energy, this requires a series of steps in s linear fashion, meaning it would be best suited to a process-style diagram.

Marta's project involves showing the steps of the cell cycle: the clue is in the name. This process is not linear, and instead repeats itself, meaning it fits to a cycle diagram (i.e. a circular diagram)

Paul is comparing and contrasting different organisms. Therefore, he should use a relationship diagram to show shared characteristics as well as features that differ.

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Blababa [14]

Answer:

Check the explanation

Explanation:

Keep two iterators, i (for nuts array) and j (for bolts array).

while(i < n and j < n) {

if nuts[i] == bolts[j] {

We have a case where sizes match, output/return

}

else if nuts[i] < bolts[j] {

what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1

}

else {

what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1

}

}

Since we go to each index in both the array only once, the algorithm take O(n) time.

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3 years ago
Jeff decides that he would pay as much as $3,000 for a new laptop computer. He buys the computer and realizes consumer surplus o
Lady_Fox [76]

Jeff pay $2,300 for his computer.

b. $2,300

<u>Explanation:</u>

Consumer surplus can be defined as the amount that the consumer is willing to pay for a product or a service. The word surplus is a synonym for something extra or excess. It corresponds to the extra benefit that the consumer gets while buying something which may be the result of some discount, sale, or negotiation.  

Jeff realizes a consumer surplus of $700 while purchasing a laptop of $3000. As the consumer surplus is $700,

the amount Jeff has paid for the laptop is: $3000 - $700

                                          : $2300

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You have been asked to write a username validation program for a small website. The website has specific rules on what constitut
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Answer:

#function to validate username

def valid_username(username):

   

   #checking is length is between 8 to 15

   length_valid=True

   if(len(username)<8 or len(username)>15):

       length_valid=False;

   

   #checking is string is alphanumeric

   alphanumeric=username.isalnum()

   

   #checking first_and_last Characters of string is not digit

   first_and_last=True

   if(username[0].isdigit() or username[len(username)-1].isdigit()):

       first_and_last=False

   

   #counting uppercase lowercase and numeric Characters in string

   uppercase=0

   lowercase=0

   numeric=0

   

   for i in username:

       if(i.isdigit()):

           numeric=numeric+1

       elif(i.isalpha()):

           if(i.isupper()):

               uppercase=uppercase+1

           else:

               lowercase=lowercase+1

               

   valid_no_char=True

   if(uppercase<1 or lowercase<1 or numeric<1):

       valid_no_char=False

           

 

   #printing the result

   print("Length of username: "+str(len(username)))

   print("All Characters are alpha-numeric: "+str(alphanumeric))

   print("First and last Character are not digit: "+str(first_and_last))

   print("no of uppercase characters in the username: "+str(uppercase))

   print("no of lowercase characters in the username: "+str(lowercase))

   print("no of digits in the username: "+str(numeric))

   

   #checking string is Valid or not

   if(length_valid and alphanumeric and first_and_last and valid_no_char):

       print("Username is Valid\n")

       return True

   else:

       print("username is invalid, please try again\n")

       return False

#loop runs until valid_username enterd by user

while(True):

   

   username=input("Enter a username: ")

   if(valid_username(username)):

       break

Explanation:

The code was created by considering all the required cases asked in the question.

In this program, I asked username from the user continuously until it enters a valid username

first it check for length of string

then check is string contains only alphanumeric characters

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than no of uppercase lowercase and numeric character

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