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jok3333 [9.3K]
3 years ago
10

Solve for x: 18x + 3x + 4 - 5 = 5(4x – 9

Mathematics
1 answer:
Luden [163]3 years ago
4 0
Answer:
X= - 44
18x+3x+4-5=5(4x9
Collect like terms
21x+4-5=5(4x-9
More variable to the left hand side and change its sign
21x-20x-1=-45
Correct like terms
X=-45+1
Which is x=-44
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Pls help I really need help pls I need Profesional at math pls pls ​
Rzqust [24]

I think $6.75 for 15 juice boxes is better because, each juice box is 0.45.

While $5.50 for 11 juice boxes is 0.50.

And if we were to add 0.50 enough times to make 15 juice boxes it would equal 7.50

RIP OFFFFFFF

THE SECOND ONE IS A WAY BETTER OF A DEAL

4 0
3 years ago
Help⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️​
Naddika [18.5K]

Step-by-step explanation:

Hope this helps, happy learning

3 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Write 7*10*10*10*10 with an exponent<br> 7*10*10*10*10=
MAVERICK [17]
7x10^4

Because there are 4 sets of 10
5 0
3 years ago
Read 2 more answers
The quotient of a number y and 22
Stels [109]
Y/22 would be the answer to your question.
4 0
3 years ago
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