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3 years ago

. Toss a coin two times. Outcome Probability

Mathematics

1 answer:

Katen [24]3 years ago

7 0

All the possibilities of two tosses are:

H - H

H - T

T - H

T - T

Probabilities:

no Heads . . . 0.25

no Tails . . . . . 0.25

one Heads . . . 0.5

one Tails . . . . . 0.5

two Heads . . . 0.25

two Tails . . . . . 0.25

at least one Heads . . . 0.75

at least one Tails . . . . . 0.75

the two results are the same . . . 0.5

the two results are different . . . 0.5

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Read 2 more answers

Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is 1690.

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is 1690.

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3 years ago

a store is selling uniform shirts for 18.95 each. if samuel has a coupon for 1/4 off the price, how much would he pay for the sh

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3 years ago

Which expression is the factored form of 2/3 x+4

scoundrel [369]

By expanding D it is clear that it is the factored form of 2/3x + 4

as 2/3x + 4 = 2/3x + 4*3/3

= 2/3x + (2*3)*(2/3). ( rearranging terms)

=2/3( x+ 2*3). ( taking 2*3 common)

=2/3( x + 6)

which is option D

hope it helped ^_^

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3 years ago