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3 years ago

. Toss a coin two times. Outcome Probability

Mathematics

1 answer:

Katen [24]3 years ago

7 0

All the possibilities of two tosses are:

H - H

H - T

T - H

T - T

<u>Probabilities</u>:

no Heads . . . 0.25

no Tails . . . . . 0.25

one Heads . . . 0.5

one Tails . . . . . 0.5

two Heads . . . 0.25

two Tails . . . . . 0.25

at least one Heads . . . 0.75

at least one Tails . . . . . 0.75

the two results are the same . . . 0.5

the two results are different . . . 0.5

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Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago

Harrison has 80 CDs in his music collection.

melamori03 [73]

Answer:

THE ANSWER IS 9 CDS THANK ME LATER

Step-by-step explanation:

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3 years ago

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krek1111 [17]

Answflasvkdiuihrytiy\ih\j

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3 years ago

What is the expanded notation for 2,909? Numbers may be used Once,More than once, or not at all.

defon

(2 x 1,000) + (9 x 100) + (9 x 1)
Always check the place values by looking at the number (2,909) and you can figure out what number to multiply it by. Guess and check if you can’t recognize it right away.

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3 years ago

Please Solve for x<br> Log15 1 =x

Fiesta28 [93]

$\bold{\log_{15} (1) = x}\\\\
\bold{\Longrightarrow~~~15^x = 1}\\\\
\Longrightarrow~~~\boxed{\bold{x = 0}}$

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3 years ago