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Sholpan [36]
4 years ago
6

Which of the following quadratic equations has no real solutions?

Mathematics
1 answer:
Virty [35]4 years ago
8 0

Answer:

C. 3x^2 + 2x + 1

Step-by-step explanation:

A. 12^2 - (4*3*12) = 0 (there's one solution.)

B. (-3)^2 - (4*3*-18) = 255 (there're 2 real solutions.)

D. 3^2 - (4*0*-3) = 9 (there're 2 real solutions.)

C. 2^2 - (4*3*1) = -18 ✅✅

if b^2 - 4ac = negative then we can say that there isn't any real solution for the equation.

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Look at the triangle below which of the following represents two of the angle measures of the triangle
Gelneren [198K]

Answer:

C. 60° and 80°

Step-by-step explanation:

Sum of triangle = 180°

Therefore,

8x + 4 + 6x - 2 + 10x + 10 = 180

Add like terms

8x + 6x + 10x + 4 - 2 + 10 = 180

24x + 12 = 180

24x = 180 - 12

24x = 168

x = 168/24

x = 7

Find each measure of the angles by substitute x = 7 into each expression

8x + 4 = 8(7) + 4 = 60°

6x - 2 = 6(7) - 2 = 40°

10x + 10 = 10(7) + 10 = 80°

The answer is 60° and 80°

6 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90

BC = 9.48

AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106

AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

8 0
3 years ago
If Jill's best friend jumped farther than 6.5 feet, then she beat the school record and
tigry1 [53]

Answer:

what is this for?

Step-by-step explanation:

BTW: 7th graders

3 0
2 years ago
Read 2 more answers
Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .
77julia77 [94]
There is one<span> last step after getting </span>x<span> = </span>3<span>. You must check </span>x<span> = </span>3<span> in the original equation to be sure that </span>x<span> = </span>3<span> does not cause a zero denominator.</span>
6 0
4 years ago
Divide. Write the quotient in lowest terms. 4\dfrac{2}{3} \div 7 =4 3 2 ​ ÷7=4, start fraction, 2, divided by, 3, end fraction,
velikii [3]

Answer:

\dfrac{2}{3}

Step-by-step explanation:

Given the quotient: 4\dfrac{2}{3} \div 7

Step 1: Write 4\dfrac{2}{3} in improper fraction.

4\dfrac{2}{3}=\dfrac{14}{3}

Therefore:

4\dfrac{2}{3} \div 7=\dfrac{14}{3} \div 7

<u>Step 2:</u> Change the division sign to multiplication by taking the reciprocal of 7

\dfrac{14}{3} \div 7 =\dfrac{14}{3} X\dfrac{1}{7} \\$Simplify\\\\=\dfrac{2}{3}

3 0
3 years ago
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